Only two real numbers satisfy x² = 23, so A is the set {-√23, √23}. B is the set of all non-negative real numbers. Then you can write the intersection in various ways, like
(i) A ∩ B = {√23} = {x ∈ R | x = √23} = {x ∈ R | x² = 23 and x > 0}
√23 is positive and so is already contained in B, so the union with A adds -√23 to the set B. Then
(ii) A U B = {-√23} U B = {x ∈ R | (x² = 23 and x < 0) or x ≥ 0}
A - B is the complement of B in A; that is, all elements of A not belonging to B. This means we remove √23 from A, so that
(iii) A - B = {-√23} = {x ∈ R | x² = 23 and x < 0}
I'm not entirely sure what you mean by "for µ = R" - possibly µ is used to mean "universal set"? If so, then
(iv.a) Aᶜ = {x ∈ R | x² ≠ 23} and Bᶜ = {x ∈ R | x < 0}.
N is a subset of B, so
(iv.b) N - B = N = {1, 2, 3, ...}
Answer:
7 vans and 1 car
Step-by-step explanation:
It MATH DO IT YURSELF
Answer:
±(√35 i)
Step-by-step explanation:
We need to solve the above equation using the imaginary unit i.
We know i= √-1
Solving
±√-35 =±( √-1 √35)
= ±(√35 i)Since 35 = 5*7 or 35*1 it cannot be further simplified
So our answer is ±(√35 i).
The answer would be 5 thousand because the decimal doesn't count and you have 268 and that's lower than 500
Answer: 2 hrs 40 min
Step-by-step explanation: Ok I might be wrong so try to do other people's answers instead of mine.
So your friend is going 6 miles per hour, so he/she will be there in an hour
But you are going 3.5 miles an hour.
So what I did was divide 3.5 by 5 and 60 by 5 and found out that you are going 0.5 miles every 20 min. Then I added up the distance and time and got 6 miles every 2 hrs and 40 min
REMINDER: I might be wrong because I haven't done this question before, but tell me if I'm right or not! :D
