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OlgaM077 [116]
4 years ago
12

Write (2b^2)^3 without exponents.

Mathematics
2 answers:
babunello [35]4 years ago
5 0
64xbxbxbxbxbxb
Because you expand
Studentka2010 [4]4 years ago
4 0

Answer:

64 * b * b * b * b * b * b

Step-by-step explanation:

Apply exponent to number first, then expand the variable's exponent into repeated multiplication.

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What is the slope of this equation? y= -1/2x −3 option -3 0 -1/2
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4 years ago
I need this help me please
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3 years ago
The number 64 has the property that it is divisible by its units digit. How many whole numbers between 10 and 50 have this prope
sineoko [7]

Answer:

\large \boxed{17}

Step-by-step explanation:

Let's call the numbers "<em>tu</em>", where<em> t</em> is the tens digit and <em>u</em> is the units digit.

We can solve this by the "brute force" method —  examining each number to see if it satisfies the conditions.

\begin{array}{cccl}\mathbf{u}&\mathbf{tu}& \textbf{Divisible by u} & \\0 &20, 30, 40 & 0 & \text{Division by zero is impossible}\\1 & 11, 21, 31, 41 & 4& \text{All numbers are divisible by one}\\2 & 12, 22, 32, 42 & 4 & \text{All even numbers are divisible by two}\\3 & 13,  23, 33, 43 & 1 &\text{Only 33 is divisible by three}\\4 & 14, 24, 34, 44 & 2 & \text{Only 24 and 44 are divisible by four}\\5 & 15, 25, 35, 45 & 4 & \text{Numbers ending in 5 are divisible by five}\\\end{array}

\begin{array}{cccl}6 & 16, 26, 36, 46 & 1 & \text{Only 36 is divisible by six}\\7 & 17, 27, 37, 47 & 0 & \text{None of the numbers is divisible by seven}\\8 & 18, 28, 38, 48 & 1 & \text{Only 48 is divisible by eight}\\9 & 19, 29, 39, 49 & 0 & \text{None of the numbers is divisible by nine}\\& \textbf{TOTAL =} &\mathbf{17}& \\\end{array}\\\text{$\large \boxed{\mathbf{17}}$ numbers between 10 and 50 are divisible by their units digit}

5 0
3 years ago
Write a real world problem that can be represented by the equation y+20=85
madam [21]
Hanna bought 85 candies and ate 20 of them. How many candies are left?
5 0
3 years ago
Read 2 more answers
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