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Ainat [17]
3 years ago
7

There are three naturally occurring isotopes of Nitrogen as follows:

Chemistry
1 answer:
jarptica [38.1K]3 years ago
4 0

Answer:

See explanation

Explanation:

a) Isotopes are variants of one chemical element which (such as Nitrogen in this case). Those variants differ in <u>neutron number</u> and <u>nucleon number</u>.

This is also the reason why they have <u>different masses</u>. Isotopes are different physically to their original atoms.

b) All isotopes of a given element have the same number of protons and electrons. All the isotopes have the same atomic number as the original element. Isotopes are almost the same chemically.

c) The 14 in the name of Nitrogen-14, means  it has a mass of 14u ( while Nitrogen 15 has a mass of 15 u). Nitrogen-14 will have the greatest affect on the average atomic mass, this because of the 95% abundance.

Nitrogen has an average atomic mass of 14.0067 u. This is the closest to 14, what shows nitrogen-14 has the biggest affect.

The average atomic mass is calculated as following: 14*0.95 +15*0.03 + 16*0.02 =14.07 u

d) Both are isotopes, but of another element. They both have a mass of 14 u. Bu they have a different number of neutrons: Oxygen-14 has 6 neutrons and 8 protons while Nitrogen-14 has 7 neutrons and 7 protons. This means oxygen-14 and nitrogen-14 are not isotopes, since isotopes do have the same number of neutrons.

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a. the solution is a base

Explanation:

The pH range is between 0 to 14.

A solution with a pH value between 0 and 6 is said to be acidic.

A solution with pH value at 7, is said to be neutral, e.g., distilled water.

A solution with pH value between 8 and 14 is a base.

Given pH = 10, a pH value of 10 falls between the base or alkali range of the indicator

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Morgarella [4.7K]

Answer:

A.) DNA is a double helix, and RNA is a single strand.



C.) DNA is involved only in transcription, and RNA is involved in both transcription and translation.



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A chemist makes of nickel(II) chloride working solution by adding distilled water to of a stock solution of nickel(II) chloride
Lady_Fox [76]

Answer:

0.0900 mol/L

Explanation:

<em>A chemist makes 330. mL of nickel(II) chloride working solution by adding distilled water to 220. mL of a 0.135 mol/L stock solution of nickel(II) chloride in water. Calculate the concentration of the chemist's working solution. Round your answer to significant digits.</em>

Step 1: Given data

  • Initial concentration (C₁): 0.135 mol/L
  • Initial volume (V₁): 220. mL
  • Final concentration (C₂): ?
  • Final volume (V₂): 330. mL

Step 2: Calculate the concentration of the final solution

We prepare a dilute solution from a concentrated one. We can calculate the concentration of the working solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂

C₂ = 0.135 mol/L × 220. mL/330. mL = 0.0900 mol/L

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3 years ago
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