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Ostrovityanka [42]
3 years ago
5

Write balanced equations for each of the processes, choosing from the following substances as reactants: BaCl2 O2 H2SO4 HNO3 C2H

5OH H2O Ca(OH)2 K Na2CrO4 KOH Pb(NO3)2
Chemistry
1 answer:
marishachu [46]3 years ago
8 0

Answer:

BaCl₂ and H₂SO₄

Explanation:

The reaction is the precipitation of BaSO₄ from solution.

This means that our reactants must contain the Ba ion and SO₄²⁻ ion.  The reactants that meet this criteria are the; BaCl₂ aand H₂SO₄

The reaction is given as;

BaCl₂ + H₂SO₄ --> BaSO₄ + 2HCl

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What mass of KNO3 would be needed to produce 18.4 liters of oxygen gas, measured at 1.50 x 10^3 kPa and 15 degrees Celsius?
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Answer:-

2328.454 grams

Explanation:-

Volume V = 18.4 litres

Temperature T = 15 C + 273 = 288 K

Pressure P = 1.5 x 10^ 3 KPa

We know universal Gas constant R = 8.314 L KPa K-1 mol-1

Using the relation PV = nRT

Number of moles of oxygen gas n = PV / RT

Plugging in the values

n = (1.5 x 10^3 KPa ) x ( 18.4 litres ) / ( 8.314 L KPa K-1 mol-1 x 288 K)

n = 11.527 mol

Now the balanced chemical equation for this reaction is

2KNO3 --> 2KNO2 + O2

From the equation we can see that

1 mol of O2 is produced from 2 mol of KNO3.

∴ 11.527 mol of O2 is produced from 2 x 11.527 mol of KNO3.

= 23.054 mol of KNO3

Molar mass of KNO3 = 39 x 1 + 14 x 1 + 16 x 3 = 101 grams / mol

Mass of KNO3 = 23.054 mol x 101 gram / mol

= 2328.454 grams

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