Answer:
26.81 moles
Explanation:
From the coefficients of the equation, we know that for every 2 moles of iron(III) oxide produced, 7 moles of oxygen are consumed.
So, the answer is 7.66(7/2), which is 26.81 mol.
The mass is
Explanation:
First, we need to find the volume of the cube.
v = lwh
v = (4)(4)(4)
v = 64 cubic cm
Now, since we know the volume and the density, we can figure out the mass.
The formula is mass = volume x density
Mass = 64 x 2.7
Mass = 172.8 g.
Therefore, the mass is 172.8 grams.
The last-Hypothesis Experiment
Answer:
2.72g
Explanation:
The balanced equation of this reaction is given as follows:
Na2O + H20 --> 2NaOH
Based on this balanced equation, 1 mole of Na2O will produce 2 moles of NaOH.
First, we need to convert mass of Na2O into moles by using the formula;
mole = mass/molar mass
Molar mass of Na2O = 23(2) + 16
= 46 + 16
= 62g/mol
mole = 2.1g/62g/mol
mole of Na2O = 0.034mol
Hence, if 1 mole of Na2O will produce 2 moles of NaOH.
Then, 0.034mol of Na2O will produce (0.034 × 2) = 0.068mol of NaOH.
To convert mole of NaOH to mass, we use;
mole = mass/molar mass
Molar mass of NaOH = 23 + 16 + 1 = 40g/mol
0.068 = mass/40
mass of NaOH produced = 2.72g.