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Lelechka [254]
4 years ago
8

Math Help? 15 Points

Mathematics
1 answer:
Helga [31]4 years ago
5 0
A) Kara's fee for the second child is $5
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An ordered pair with a a negative x and positive y coordinate is located in which quadrant?
Ivanshal [37]

Answer:

Quadrant II

Step-by-step explanation:

Quadrant I is ( + , + )

Quadrant II is ( - , + )

Quadrant III is ( - , - )

Quadrant IV is ( + , - )

6 0
3 years ago
Read 2 more answers
When you read carefully in order to determine the meaning of a challenging word,you are
aivan3 [116]

Answer: Using context clues

Step-by-step explanation:

5 0
4 years ago
A vending machine sells chips at $0.40 and candy at $0.50. Last month, the vending machine yielded $139.80 with a sale of 298 it
Sidana [21]
Let us say... . the machine sold packages of chips at the amount of "p",
and the machine also sold, last month as well, an amount of "c" candies

now, last month the machine sold total 298 items
that yielded a revenue of $139.80

so...whatever "p" and "c" are, we know that, their sum for last month is,
298, so,
p + c = 298

how much revenue in sales of chips? well, they're 0.40 per package,
so, whatever "p" is, the machine sold 0.40 * p or 0.4p in revenue

how much for the candies? well, they're 0.50 for each, so
whatever "c" is, 0.50 * c or 0.5c in revenue

we know, their total revenue yield was 139.80
so
0.4p + 0.5c = 139.8

now... do substitution from the 1st equation on the 2nd one, and solve for "p", or packages of chips

that is \begin{cases}
p+c=298\to c=\boxed{298-p}
\\ \quad \\
0.4p+0.5c=139.8
\\
\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\
0.4p+0.5(\boxed{298-p})=139.8

\end{cases}\impliedby \textit{solve for "p"}
6 0
3 years ago
You and your friend are comparing two loan options for a $165,000 house. Loan 1 is a 15-year loan with an annual interest rate o
Harlamova29_29 [7]

Answer:

No, he is wrong.

Step-by-step explanation:

Since, the total payment of a loan after t years,

A=P(1+r)^t

Where,

P = present value of the loan,

r = rate per period ,

n = number of periods,

Given,

P = $165,000,

In loan 1 :

r = 3% = 0.03, t = 15 years,

So, the total payment of the loan is,

A_1 = 165000(1+0.03)^{15}=165000(1.03)^{15}\approx \$ 257,064.62

In loan 2 :

r = 4% = 0.04, t = 30 years,

So, the total payment of the loan is,

A_2 = 165000(1+0.04)^{30}=165000(1.04)^{30}\approx \$ 535,160.59

Since, A_1 < A_2

Hence, total amount repaid over the loan will be less for Loan 1.

That is, the friend is wrong.

7 0
3 years ago
I need help on number 1.
GaryK [48]
I think about 7 1/4 I hope I helped You!!
7 0
4 years ago
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