So the sum of two sides are 2x+2y and the perimeter is 3x+3y. So if we subtract the two sides from the perimeter we will have the dimension of the final side....
3x+3y-2x-2y=x+y which is the same as the other two sides, thus this is an equilateral triangle.
...
Again we will subtract the sum of two sides from the perimeter to find the measure of the third side...
7x+2y-2x-y-3x+5y
2x+6y is the third side...
Answer: he watched 1/12 of the movie at night.
Step-by-step explanation:
Let x represent how much of the movie that he watched at night.
Tanner watched 1/4 of a movie in the morning, and he watched some at night. This means that she had already watched
x + 1/4 = (4x + 1)/4 of the movie by the end of the day. Therefore, what he has left to watch would be
1 - (4x + 1)/4 = [4 - (4x + 1)]/4
= (3 - 4x)/4
By the end of the day, he still had 2/3 of the movie to watch, it means that
(3 - 4x)/4 = 2/3
Cross multiplying, it becomes
3(3 - 4x) = 4 × 2
9 - 12x = 8
12x = 1
x = 1/12
No.
The maximum possible area given a constant amount of material for a quadrilateral will always be a square.
For example if the material for the perimeter is 64 we can form a rectangle that is 22 by 10 which will have an area of 220 u^2.
However a square using the same amount of material will have sides of 64/4=16 and an area of 16^2=250 u^2
So in general the area is maximize the closer the sides are to being equal and minimized as the difference between the sides becomes greater. In the case of comparing the material, perimeter, of a rectangle to a square for the same amount of material the square will use less material than the rectangle.
A square can have a smaller perimeter and a greater area that a rectangle.
In the example above the rectangle had a perimeter of 64 u and an area of 220 u^2. If we made a square with just 60 u, it would have an area of 225 u^2.
Answer:

Step-by-step explanation:
Hello!
The HCF or the highest common factor (sometimes also known as the greatest common factor, GCF), is the greatest factor between terms.
First, let's expand both terms:
If we keep them on top of another, we can see that the overlapping variables are
, meaning that the greatest common factor between them is
.