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inn [45]
3 years ago
6

0.5t+0.25(t+16)=4+0.75 help please!!

Mathematics
2 answers:
Zigmanuir [339]3 years ago
6 0
X is equal to the number 1
Jlenok [28]3 years ago
6 0

Answer:

Step-by-step explanation:

0.5t+0.25(t+16)=4+0.75t

=>0.5t+0.25t+0.25x16 =4+0.75t

=>0.75t+4=4+0.75t

=>0.75t+4-4=0.75t        [subtract 4 from both sides]

=>0.75t=0.75t

=>0.75t-0.75t=0            [subtract 0.75t from both sides]    

=>0=0

so,the equation has no solution.

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(08.06 LC)
AVprozaik [17]

Answer:

First one

Step-by-step explanation:

Variable b is 7 more than variable c:

b = c + 7

Variable b is also 1 less than variable c:

b = c - 1

4 0
2 years ago
Read 2 more answers
Please asap this is the only question and I'm also running out of time thank youuuuu
Wittaler [7]
One question, and no one answered it for you?

Simple,

the answer is....(6,5) Point of Intersection.

I triple checked my work. :)


7 0
2 years ago
Solve the quadratic equation by completing the square.<br> =+x^2+16x +61=0
Vlad1618 [11]
X^2 + 16x + 61 = 0
x^2 + 16x = -61
x^2 + 16x + 64 = -61 + 64
(x + 8)^2 = 3
x + 8 = (+-) sqrt 3
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x = -8 + sqrt 3...and x = -8 - sqrt 3 <== ur solutions

3 0
3 years ago
Suppose "35" cars start at a car race. In how many ways can the top 3 cars finish the​ race?
Thepotemich [5.8K]

Answer:

The  value  is   \left 35  } \atop }} \right. P_3  =  39270

Step-by-step explanation:

From the question we are told that

    The  total number of cars is  n  =  35

     The  number cars considered is  r = 3

Generally the number of different top three finishes possible for this race of 35 cars  is mathematically represented as

       \left n } \atop }} \right. P_r  =   \frac{n!}{(n - r) !}

       \left 35  } \atop }} \right. P_3  =   \frac{35! }{(35 - 3) !}

       \left 35  } \atop }} \right. P_3  =   \frac{35 *  34 *  33 *  32! }{32 !}

       \left 35  } \atop }} \right. P_3  =  39270

7 0
2 years ago
Help me plzzz i don't know what to put​
Pachacha [2.7K]
The correct answer should be 4. 2 times 0.3 is 0.6. 3.4 plus 0.6 equals 4. ;)
7 0
2 years ago
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