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DiKsa [7]
3 years ago
13

H - 16 ≤ - 24

Mathematics
1 answer:
just olya [345]3 years ago
7 0

This are the answers to your questions

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Solve 7x − 2(x + 1) = 6x + 14.<br> −12<br> 12<br> −16<br> 16
Vladimir79 [104]
7x-2(x+1)=6x+14
7x-2x-2=6x+14
5x-6x=14+2
-x=16
x=-16
3 0
3 years ago
Read 2 more answers
In a recent​ year, 304 of the approximately​ 300,000,000 people in the United States were struck by lightning. Estimate the prob
umka2103 [35]

Answer:

\frac{19}{18,750,000}=0.0000010133333333

Step-by-step explanation:

We have been given that in a recent​ year, 304 of the approximately​ 300,000,000 people in the United States were struck by lightning.

\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Number of possible outcomes}}

\text{P( A randomly selected person in the United States will be struck by lightning this year)}=\frac{304}{300,000,000}

\text{P( A randomly selected person in the United States will be struck by lightning this year)}=\frac{19}{18,750,000}

\text{P( A randomly selected person in the United States will be struck by lightning this year)}=0.0000010133333333

Therefore, the probability that a randomly selected person in the United States will be struck by lightning this year is \frac{19}{18,750,000}=0.0000010133333333.

6 0
3 years ago
Read 2 more answers
An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume
Lynna [10]

Answer:

a) 21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

b) ME=2.58\frac{52}{\sqrt{350}}=7.17

c) ME=2.58\frac{52}{\sqrt{100}}=13.42

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

\bar X=21 represent the sample mean  

\mu population mean (variable of interest)  

\sigma=52 represent the population standard deviation  

n=350 represent the sample size  

99% confidence interval  

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58  

Now we have everything in order to replace into formula (1):  

21-2.58\frac{52}{\sqrt{350}}=13.83  

21+2.58\frac{52}{\sqrt{350}}=28.17  

So on this case the 99% confidence interval would be given by (13.83;28.17)  

Part b

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{350}}=7.17

Part c

The margin of error is given by:

ME=2.58\frac{52}{\sqrt{100}}=13.42

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

6 0
3 years ago
Triangle EFG has the following vertices E(1,2), F(4,2) and G(1,6). What are the new coordinates of triangle E’F’G’ after it is r
Fynjy0 [20]

Answer:

i dont know but

Step-by-step explanation:

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7 0
3 years ago
What is the value of the expression below when y=10? 5y+3
trasher [3.6K]
I think it is 53 that’s what i would put if i were u
7 0
3 years ago
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