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Elena L [17]
3 years ago
12

Nadia is making a copy of an image on the copy machine. She needs to enlarge it, and decides to enlarge it by a scale factor of

three. If one side of the original is 1 1/2 in., how big is that same side after she makes the copy?
Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
7 0
The new side will measure;
3/2*3
=9/2
=4.5 inches
PIT_PIT [208]3 years ago
5 0

Answer:

4\frac{1}{2}in

Step-by-step explanation:

We know that one side of the original is

1\frac{1}{2}in

Also, the copy machine enlarges the original by a scale factor of three. This means that the enlarged result is three times bigger that the original. Remember that a scale factor multiplies the original measure.

So, the bigger copy would be

3\times 1\frac{1}{2}in=3 \times \frac{3}{2}=\frac{9}{2}=4\frac{1}{2}in

Therefore, the image changed from 1\frac{1}{2}in to 4\frac{1}{2}in.

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What are the real zeros of x^3+4x^2-9x-36
Katyanochek1 [597]

Answer:

x = -4\\x = -3\\x = 3

Step-by-step explanation:

To find the real zeros you must match the function to zero and factor the expression.

We have a polynomial of degree 3.

We try to group the terms to perform the factorization

x ^ 3 + 4x ^ 2-9x-36 = 0\\\\x ^ 2(x + 4) - 9(x + 4) = 0

Now we take (x + 4) as a common factor

(x + 4)(x ^ 2 -9) = 0

If we have an expression of the form (a ^ 2-b ^ 2) we know that this expression is equivalent to:

(a ^ 2-b ^ 2) = (a + b)(a-b)

In this case

a = x\\b = 3

So:

(x ^ 2 -9) = (x + 3)(x-3)

Finally:

x ^ 3 + 4x ^ 2-9x-36 = (x + 4)(x + 3)(x-3) = 0

The solutions are:

x = -4\\x = -3\\x = 3

6 0
3 years ago
B is the midpoint of AC and D is the mid point of CE solve for x given BD=3x + 5 and AE= 4x+20
Elena L [17]

Answer:triangle BCD is similar to triangle ACE (side, angle C, side)

AC = 2 BC

therefore AE = 2 BD

therefore

4x+20 = 2 (3x+5) solve that


Step-by-step explanation:


8 0
3 years ago
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