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3 years ago

How do you subtract mixed fractions?

1 answer:

5 0

Make it an improper fraction by multiplying the whole number by the denominator then adding the numerator then find the common denominator (remember what you do to the bottom, you do to the top) then subtract normally.

eg. 1 4/5 - 1 7/10

= 9/5 - 17/10

= 18/10 - 17/10

= 1/10 or 0.1

Hope this helps!

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Which statements are always true regarding the

umka21 [38]

C) m∠5 + m∠6 =180°

D) m∠2 + m∠3 = m∠6

E) m∠2 + m∠3 + m∠5 = 180°

Step-by-step explanation:

TRUST ME! JUST TOOK MY QUIZ ON E2020

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3 years ago

D 8. Solve.

melisa1 [442]

Does it say 84 or 8.4?

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3 years ago

Gina walked 0.8 miles before she started jogging at an average pace of 6 miles per hour. The equation d = 0.8 + 6t can be used

Gala2k [10]

Answer:

independent: t
dependent: d

Step-by-step explanation:

The way the equation is written, d is the dependent variable; t is the independent variable (on which d depends).

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4 years ago

Read 2 more answers

Solve the given equation over the interval [0, 2π): csc^2 x + 2 csc x = 0.

Anastaziya [24]

$csc^2x+2cscx=0$
Factor out the GCF which is csc x
$cscx(cscx+2)=0$
Set each factor equal to zero.
$cscx=0$ or $cscx+2=0$
Using the reciprocal sine function we can replace csc in the equations.
$\frac{1}{sinx} =0$ or $\frac{1}{sinx} +2=0$
The first equation yields 1 = 0 which is not true. However the second equation does offer 2 possible answers.
When solved for sinx you get $sinx=- \frac{1}{2}$
The sine function is negative in the 3rd and 4th quadrants.
You can use the unit circle or the $sin^-^1$ feature on your calculator $sin^-^1(1/2)$
$210^o or 330^o$ alter radian answer which is probably what you want is $\frac{7 \pi }{6} or \frac{11 \pi }{6}$

8 0

3 years ago

Which can be multiplied?

elena55 [62]

Answer:

B) BD

Step-by-step explanation:

The number of columns of the first matrix (2nd dimension) must match the number of rows of the second matrix (1st dimension). When you write the dimensions together, the two middle numbers must be the same.

AB ⇒ (3x2) × (3x5) . . . . 2 ≠ 3, so cannot be multiplied

BD ⇒ (3x5) × (5x7) . . . . 5 = 5, so can be multiplied

CD ⇒ (2x3) × (5x7) . . . . 3 ≠ 5, so cannot be multiplied

DD ⇒ (3x5) × (3x5) . . . . 3 ≠ 5, so cannot be multiplied

8 0

3 years ago