Answer:

<h3>Hence, it will take 12 minutes by the printer to use all 96 sheets of paper.</h3>
Step-by-step explanation:
Given :
Tanya is printing a report.
There are 96 sheets of paper in the printer, and the number of sheets of paper p left after t minutes of printing is given by the function

When all the 96 sheets printed , then the number of sheets will left to print =0
Substitute p(t)=0 in the given function, to find the value of t, we get

<h3>Hence, it will take 12 minutes by the printer to use all 96 sheets of paper.</h3>
We are given the ratio of 1/2 inch: 18 miles
Multiply both sides of the ratio by 2. I'm doing this so that the "1/2" turns into "1"
So we go from this ratio
1/2 inch: 18 miles
to this ratio
1 inch: 36 miles
which means that every inch on paper represents 36 miles in real life
----------------------------------------------------------------
The question is now: if two towns are 2.5 inches apart on paper, then how far are they in real life? (note: 2.5 is the decimal form of 2 and a half)
To find out, multiply both sides by 2.5
1 inch: 36 miles
2.5*(1 inch): 2.5*(36 miles)
2.5 inches: 90 miles
--------------------------------------------------------------------------
Answer: The two towns are 90 miles apart in real life
Answer:2 and 4 and the second one is 7 and 8
Step-by-step explanation:
Correct
m<2 = 125
m<8 = 55
m<14 = 100
m<16 = 80
Supposing that the stock increases in 37 days, the 95% confidence interval for the proportion of days JMJ stock increases is: (0.484, 0.7292)
- The lower bound is of 0.484.
- The upper bound is of 0.7292.
- The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of
.
Supposing that it increases on 37 out of 61 days:
95% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the proportion of days JMJ stock increases is (0.484, 0.7292), in which 0.484 is the lower bound and 0.7292 is the upper bound.
The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>
A similar problem is given at brainly.com/question/16807970