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Reika [66]
3 years ago
14

I NEED ANSWERS FAST!!!

Mathematics
1 answer:
uranmaximum [27]3 years ago
5 0

Answer:

if I counted right its 11 they would equal money at 152 dollars

Step-by-step explanation:

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Find the total surface area of the<br> following square pyramid:<br> 6 cm<br> 8 cm
Norma-Jean [14]

Answer:

Surface area of square pyramid = 160cm^{2}

Step-by-step explanation:

Let, b is the length of the base and s is the slant height

According to given condition:

b = 8 cm

s = 6 cm

Find out:

Surface area of square pyramid = ?

Formula:

Surface area of square pyramid = b^{2} + 2bs

Solution:

Surface area of square pyramid = b^{2} + 2bs

Surface area of square pyramid = 8^{2} + 2(8)(6)

Surface area of square pyramid = (64+ 96 ) cm^{2}

Surface area of square pyramid = 160cm^{2}

8 0
3 years ago
Principal 47,000<br> Rate of interest 5 5 over 8% <br> Time 3 months<br> Simple interest ?
Ainat [17]
I= PRT
I= (47000)(5/.08)(.3)
I= 881,250
6 0
3 years ago
Read 2 more answers
Find two integers whose product is 138 such that one of the integers is seven less than five times the other integer.
Oksana_A [137]

Answer: the integers are 6 and 23

Step-by-step explanation:

Let x represent one of the integers.

Let y represent the other integer.

The product of the integers is 138. This means that

xy = 138 - - - - - - - - - -1

One of the integers is seven less than five times the other integer. This means that

x = 5y - 7

Substituting x = 5y - 7 into equation 1, it becomes

y(5y - 7) = 138

5y² - 7y = 138

5y² - 7y - 138 = 0

5y² + 23y - 30y - 138 = 0

y(5y + 23) - 6(5y + 23)

y - 6 = 0 or 5y + 23 = 0

y = 6 or y = - 23/5

The only possible value of y is 6

x = 138/y = 138/6

x = 23

4 0
3 years ago
I need help can someone help me (:
vladimir2022 [97]
Hey there!

To solve the first problem, I've found it easiest to solve the equation for, say, values –2 through +2 and create a table of values for you to begin graphing this function. You may need to do more depending on the equation itself. 

Some points are: (–2, 0.75), (–1, 1.5), (0, 3), (1, 6) and (2, 12). You can check which graph matches up with these points the closest to get your answer of D. 

To solve the second problem, you'll need to use the distance equation.

x1 = –4, y1 = 3
x2 = –1, y2 = 1 
  ___________________
√ (x2–x1)^2 + (y2–y1)^2
  _________________
√ (–1–(–4)^2 + (1–3)^2
  _______________
√ (–1+4)^2 + (–2)^2
  ____________
√ (3)^2 + (–2)^2
  _____
√ 9 + 4
  ___
√ 13, making your answer D

For your third question, I always just counted the number of units the point was from the line of reflection. You'll count twice diagonally towards the line from point C for this one, staying on the "crosshairs" of the graph. All you need to do then is count two diagonal units along the same line, then you'll get your answer of (2, 6), or D. 

For your final question, A and B are immediately out, since they won't be parallel to the 4x equation. You'll need to solve both of your remaining equations for y with 2 plugged in for x; whichever one equals 7 will be your answer. In this case, it will be D. 

Hope this helped you out! :-)
3 0
3 years ago
42 ÷ 7 = help me i need to finish in 2 min
victus00 [196]

Answer:

6

Step-by-step explanation:

6 X 7 = 42

7 0
4 years ago
Read 2 more answers
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