Answer:
B
Step-by-step explanation:
We know that:
-measuring a cone
-diameter: 18 units
-height: 8 units
We need to know how to find the volume of this cone. To do this, we need the equation to find the volume of a cone:
where r=radius and h=height
Upon assessing this equation we also now know that we are missing a radius.
For a circle, the radius is the distance from the midpoint, center, to the border of the circle. The diameter is the distance from the border of one circle to another, passing through the midpoint. Knowing this, we can conclude that the diameter is two times the radius.
Using this information we can figure out the radius for this cone: 9 units.
Now that we have the radius, we can plug in the rest of the numbers with the correct placements.
square the 9 by calculating 9 times 9.
combine like terms and keep pi separate.
V=216
cubic units
Since this problem is asking for volume, we will used cubic units.
Answer:
![\left[\begin{array}{cc}0&-1\\-1&0\\-1&-1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0%26-1%5C%5C-1%260%5C%5C-1%26-1%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
In this question we have to subtract the corresponding entries of column of matrix 1 and the matrix 2 corresponding entries
![=\left[\begin{array}{cc}-1&0\\1&-2\\1&3\end{array}\right]-\left[\begin{array}{cc}-1&1\\2&-2\\2&4\end{array}\right] \\=\left[\begin{array}{cc}-1-(-1)&0-1\\1-2&-2-(-2)\\1-2&3-4\end{array}\right]\\=\left[\begin{array}{cc}-1+1&-1\\-1&-2+2\\-1&-1\end{array}\right]\\=\left[\begin{array}{cc}0&-1\\-1&0\\-1&-1\end{array}\right]](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%260%5C%5C1%26-2%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%261%5C%5C2%26-2%5C%5C2%264%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1-%28-1%29%260-1%5C%5C1-2%26-2-%28-2%29%5C%5C1-2%263-4%5Cend%7Barray%7D%5Cright%5D%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%2B1%26-1%5C%5C-1%26-2%2B2%5C%5C-1%26-1%5Cend%7Barray%7D%5Cright%5D%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0%26-1%5C%5C-1%260%5C%5C-1%26-1%5Cend%7Barray%7D%5Cright%5D)
Answer:
d.
Step-by-step explanation:
if x varies directly as y,
x = ky
8 = 12k
12k = 8
k = 8/ 12
k = 2/3,
x = 2/3 y
now substitute the value of any of the numbers of each pair, and check if it works:
for e.g, find x when y = 15
x = 2/3y
x = 2/3 × 15
x = 10
since you obtain x = 10 when y = 15, the pair is a possible corresponding value of x and y. now do the same for the rest .
ii) x = 2/3y
x = 2/3 × 3, when y = 3
x = 2
hence, this is also a possible pair of x and y values.
iii) x = 2/3y
x = 2/3 × 9 when y = 9
x = 6
again, a possible pair of x and y values.
iv) x = 2/3y
x = 2/3 × 20 when y = 20
x = 40/3
here, when y = 20, x is not 15. it is 40/3.
thus, it can be determined that this is not a possible pair of x and y values.
please try to understand and have a great day!
Answer:
Step-by-step explanation: