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Dmitry_Shevchenko [17]
2 years ago
14

Using addition rules, show how to add the two real numbers. 7 + (-14)

Mathematics
2 answers:
Debora [2.8K]2 years ago
5 0
Hello there! Using the rules of addition, we can identify that when adding a positive to a negative number, the result shifts toward the positive side but takes the sign of the greater number. It will be demonstrated in this problem to simplify how problems like this are solved:

Step 1: Rewrite the problem

-14 + 7 = ?

Step 2: Since we’re adding 7 to a negative number, that means the negative number decreases by the quantity it’s being added by.

This means we would have to really subtract 7 from 14 to get 7.

Step 3: Keep the sign of the greater number

Since 14 is greater than 7, we will keep the negative sign in accordance.

Step 4: Simplify

-14 + 7 = -7

Using the rules of addition, we will find that -14 + 7 = -7. If you need additional help, let me know and I will gladly assist you.
ozzi2 years ago
3 0

Answer:

- 7

Step-by-step explanation:

note that

+ (- ) = - ( adding a negative is equivalent to subtraction )

- (- ) = + ( subtracting a negative is equivalent to addition )

then

7 + (- 14) = 7 - 14 = - 7

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Answer:

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Step-by-step explanation:

First let's find the value of 'p-q':

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To find |p-q| (module of 'p-q'), we can use the formula:

|ai + bj| = \sqrt{a^{2}+b^{2}}

Where 'a' is the coefficient of 'i' and 'b' is the coefficient of 'j'

So we have:

|p - q| = |15i + 20j| = \sqrt{15^{2}+20^{2}} = 25

Now, we need to find the module of p and the module of q:|p| = |9i + 12j| = \sqrt{9^{2}+12^{2}} = 15

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Then, evaluating |p-q|-{|p|-|q|}, we have:

|p-q|-(|p|-|q|) = 25 - (15 - 10) = 25 - 5 = 20

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