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Natalija [7]
3 years ago
9

EASY QUESTION Is the unknown side a leg or hypotenuse?

Mathematics
2 answers:
Artemon [7]3 years ago
7 0

Answer:

the unknown side is hypotenuse.

Vinvika [58]3 years ago
7 0
The unknown side is the hypotenuse it’s always going to be the longer side
You might be interested in
Diameter of wheel of car is 35 cm . how much distance will it cover in 1000 revolution.
kirill115 [55]

Answer: 35000π cm.

Step-by-step explanation:

First find circumference

Circumference = 2 × π × radius

Circumference = 2 × π × ( diameter / 2 )

Circumference = 2 × π × ( 35 / 2 )

Circumference = 35 × π cm

Now,

1 revolution = 1 circumference

1000 revolution = 1000 circumference

1000 revolution = 1000 × (35 × π)

1000 revolution = 35000π cm.

7 0
3 years ago
In science class, Paul estimates the volume of a sample to be 37 mL. The actual volume of the sample is 39 mL. Find the percent
svet-max [94.6K]

Answer:

the answer is 5.1%

Step-by-step explanation:

first you divide 37 by 39 to get .94871795

next you would subtract 1 by that number and you get

.05128205 which can be rounded to .051 or 5.1%

7 0
3 years ago
Julie wrote the rate $108 in 6 weeks as a unit rate.Find her mistake and correct it.
natima [27]
Well for starters that would be $108/6 weeks when a unit rate is anything over one. To put it as a unit rate (how many dollars per hours) you just divide $108 by 6 (since you would divide 6 by 6 to get) and the unit rate would end up being $18 per hour.
6 0
3 years ago
Solve the following equation x(x + 19) = -34
xxMikexx [17]
Hi there,

x(x + 19) = -34

I'm going to solve your equation step-by-step.<span><span>x<span>(<span>x + 19</span>) </span></span>= <span>−34

</span></span>Step 1: Simplify both sides of the equation.<span><span><span>x2 </span>+ <span>19x </span></span>= <span>−34

</span></span>Step 2: Subtract -34 from both sides.<span><span><span><span>x2 </span>+ <span>19x </span></span>− <span>(<span>−34</span>) </span></span>= <span><span>−34 </span>− <span>(<span>−34</span>)

</span></span></span><span><span><span><span>x2 </span>+ <span>19x </span></span>+ 34 </span>= 0

</span>Step 3: Factor left side of equation.<span><span><span>(<span>x + 2</span>) </span><span>(<span>x + 17</span>) </span></span>= 0

</span>Step 4: Set factors equal to 0.<span><span><span>x + 2 </span>= <span><span><span>0<span> or </span></span>x </span>+ 17 </span></span>= 0

</span><span><span>x = <span>−<span><span>2<span> or </span></span>x </span></span></span>= <span>−17

</span></span>Answer:<span><span>x = <span>−<span><span>2<span> or </span></span>x </span></span></span>= <span>−<span>17

Hope this helps! :)</span></span></span>
5 0
3 years ago
Read 2 more answers
MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
ioda

Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

                                    lw+2lh+2wh = 64

If we plug in what we just got, we would have

                                 l^{2} + l^{2} + l^2   =  64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}

                       

                                                 

7 0
4 years ago
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