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2 years ago

9(8s - 5f) use f = 3 and s = 4

Mathematics

2 answers:

Savatey [412]2 years ago

5 0

Answer:

153

Step-by-step explanation:

8x4=32

5x3=15

32-15=17

9x17=153

marin [14]2 years ago

3 0

Answer:

fhmjjjjj hjk, k

Step-by-step explanation:

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A rectangle is 2 4/5 M wide and 3 and 1/2 meters long what is its area

postnew [5]

2 4/5=14/5, 3 1/2=7/2
A=l*w
14/5*7/2=98/10
98/10=9 8/10, 9 4/5
A= 9 4/5

Answer: Its area is 9 4/5m^2

8 0

2 years ago

Read 2 more answers

The triangles below are similar. Find x showing the proportion and all work.

zavuch27 [327]

we are given that

two triangles are similar

so, the ratio of their sides must be same

we get

$\frac{2}{6} =\frac{x}{x+2}$

now, we can solve for x

step-1: Cross multiply both sides

$2(x+2) =6x$

step-2: Simplify left side

$2x +4 =6x$

step-3: Subtract both sides by 2x

$2x +4-2x =6x-2x$

$4 =4x$

step-4: Divide both sides by 4

$x=1$

so,

$x=1$ ............Answer

7 0

2 years ago

What are the four points of intersection between 4x^2 + y^2 - 4y - 32 = 0 and x^2 - y - 7 = 0 ? Solve algebraically

tensa zangetsu [6.8K]

Remember (a²-b²)=(a-b)(a+b)

solve for a single variable
solve for y in 2nd

add y to both sides
x²-7=y
sub (x²-7) for y in other equaiton

4x²+(x²-7)²-4(x²-7)-32=0
expand
4x²+x⁴-14x²+49-4x²+28-32=0
x⁴-14x²+45=0
factor
(x²-9)(x²-5)=0
(x-3)(x+3)(x-√5)(x+√5)=0
set each to zero

x-3=0
x=3

x+3=0
x=-3

x-√5=0
x=√5

x+√5=0
x=-√5

sub back to find y

(x²-7)=y

for x=3
9-7=2
(3,2)

for x=-3
9-7=2
(-3,2)

for √5
5-7=-2
(√5,-2)

for -√5
5-7=-2
(-√5,-2)

the intersection points are

(3,2)
(-3,2)
(√5,-2)
(-√5,-2)

8 0

3 years ago

The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78

____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

$m-t_{a/2,n-1}\frac{s}{\sqrt{n} }$ ≤ μ ≤ $m+t_{a/2,n-1}\frac{s}{\sqrt{n} }$

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and $t_{a/2,n-1}$ is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and $t_{0.05,9}$ by 1.8331, we get that the 90% confidence interval for the mean speed is: