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steposvetlana [31]
3 years ago
8

Algebra 1 help please

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
7 0
Short leg = 18 Long leg= 24 Hypotenuse= 30 My calculations were simple trial and error. I started with a trial of 10 for the short leg to begin with, averaging and estimating the appropriate proportions based off 6 additional increments. Sorry I don't have an algebraic method for you. Hope this has helped somewhat :)
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What reasoning and explanations can be used when solving radical equations and how do extraneous solutions arise from radical eq
Mkey [24]

Answer:

We know that, a 'radical equation' is an equation that contains radical expressions, which further are the expressions containing radicals ( square roots and other roots of numbers ).

In order to solve radical equations, we use the rules of exponents and basic algebraic properties.

The common reasoning to use while solving a radical equation is:

1. Isolate the radical expression.

2. Square both sides of the equation to remove radical.

3. After removing the radical, solve the equation to find the unkown variable

4. Check the answer for the errors occurred by removing the radicals.

For e.g. \sqrt{x}-3=5

i.e. \sqrt{x}-3+3=5+3 ( Adding 3 on both sides )

i.e. \sqrt{x}=8

i.e. (\sqrt{x})^{2} =8^{2}

i.e. x=64.

So, the solution the the radical equation \sqrt{x}-3=5 is x = 64.

Further, we know that an 'extraneous solution' is that root of the radical equation which is not a root of the original equation and is excluded from the domain.

for e.g. Take \sqrt{x+4} =x-2

i.e. (\sqrt{x+4})^{2} =(x-2)^2

i.e. x+4=x^2+4-4x

i.e. 0=x^2-5x

i.e. 0=x(x-5)

i.e. x = 0 and x = 5.

Substituting x = 0 in \sqrt{x+4} =x-2, gives \sqrt{0+4} =0-2 i.e. \sqrt{4} =-2 i.e. 2=-2, which is not possible.

So, x = 0 is a solution that does not satisfy the equation.

Hence, x = 0 is an extraneous solution.

7 0
3 years ago
Customers arrive at a bank at a rate of 12/hour. It takes the clerk on average 4 minutes to help each customer. a. What is the a
-Dominant- [34]

Answer:

Step-by-step explanation:12 customers per hour..

4minutes per customer..

Time customers must wait= 12customers ×4minutes =48 minutes.. The clerk use 48minutes to attend to 12customers in one hour leaving him with 12spare minutes.

(B)since the clerk has 12 minute to spare it means each customer have a minute to wait before getting attention..

(C)number of customers waiting =12/2=6customers...

4 0
3 years ago
Help me please I need help on this question
Elena L [17]
The answer would be the 3rd choice because this is a translation
8 0
3 years ago
A company has 875 employees. "Half - Price Wednesday," 64% of the employees eat lunch at the company cafeteria. How many employe
Vika [28.1K]
875 × .64= 560

answer: 560 employees eat lunch at the cafeteria on Wednesday.
4 0
3 years ago
Read 2 more answers
Joseph drove for hours at the speed of 40 km per hours he changed his speed to 65 km for the next 2 hours how far had Joseph dri
daser333 [38]

Answer:

The answer to your question is 450 km

Step-by-step explanation:

Data

First stage                      Second stage

speed 1 = 40 km/h         speed 2 = 65 km/h                      

time 1 = 8 h                     time 2 = 2 h

Process

1.- Write the formula to calculate the speed

    speed = distance / time

-Solve for distance

    distance = speed x time

2.- Calculate the distance of the first stage

    distance 1 = 40 x 8

    distance 1 = 320 km

3.- Calculate the distance of the second stage

    distance 2 = 65 x 2

    distance 2 = 130 km

4.- Calculate the total distance

    Total distance = 320 + 130

                             = 450 km

6 0
3 years ago
Read 2 more answers
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