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ivanzaharov [21]

3 years ago

10

In order to keep a boat from drifting away, the boat is tied to a pier with a 60-foot rope. When the boat drifts as far from the

pier as the rope will allow, the rope forms a 15° angle relative to the horizontal water line.
To the nearest foot, find the maximum horizontal distance, d, that the tied-up boat can drift from the pier.

16 feet
37 feet
58 feet
62 feet

1 answer:

Rus_ich [418]3 years ago

6 0

The answer is C) hope this helped!

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Alja [10]

Oooooo child i wish i could help

5 0

3 years ago

It was wartime when the Ricardos found out Mrs. Ricardo was pregnant. Ricky Ricardo was drafted and made out a? will, deciding t

ElenaW [278]

Answer:The girl will get $2,000, the mother $4,000 and the boy $8,000

Step-by-step explanation:

f the amount the girl gets = x

The mother gets twice as much as the girl = 2x

And the boy get twice as much as the mother = 4x

Overall

x + 2x + 4x = $14,000

7x = $14,000

Divide both sides by 7 so

x=$2,000

5 0

3 years ago

A genetic experiment involving peas yielded one sample of offspring consisting of 437437 green peas and 129129 yellow peas. Use

navik [9.2K]

Answer:

The null hypothesis: $\mathbf{H_o: p=0.27}$

The alternative hypothesis: $\mathbf{H_1: p \neq 0.27}$

Test statistics : z = −2.30

P-value: = 0.02144

Decision Rule: Since the p-value is lesser than the level of significance; then we reject the null hypothesis.

Conclusion: We accept the alternative hypothesis and conclude that under the same circumstances the proportion of offspring peas will be yellow is not equal to 0.27

Step-by-step explanation:

From the given information:

Let's state the null and the alternative hypothesis;

Since The claim is that 27% of the offspring peas will be yellow.

The null hypothesis state that the proportion of offspring peas will be yellow is equal to 0.27.

i.e

$\mathbf{H_o: p=0.27}$

The alternative hypothesis state that the proportion of offspring peas will be yellow is not equal to 0.27

$\mathbf{H_1: p \neq 0.27}$

<u>The test statistics:</u>

we are given 437 green peas and 129 yellow apples;

Hence;

$\hat p = \dfrac{x}{n}$

where ;

$\hat p$ = sample proportion

x = number of success

n = total number of the sample size

$\hat p = \dfrac{129}{437+129}$

$\hat p = \dfrac{129}{566}$

$\mathbf{\hat p = 0.2279}$

Now; the test statistics can be computed as :

$z = \dfrac { \hat p -p }{\sqrt {\dfrac{p(1-p)}{n} } }$

$z = \dfrac {0.2279 -0.27 }{\sqrt {\dfrac{0.27(1-0.27)}{566} } }$

$z = \dfrac {-0.043 }{\sqrt {\dfrac{0.27(0.73)}{566} } }$

$z = \dfrac {-0.043 }{\sqrt {\dfrac{0.1971}{566} } }$

$z = \dfrac {-0.043 }{\sqrt {3.48233216*10^{-4} } }$

$z = \dfrac {-0.043 }{0.01866} }$

z = −2.30

C. P-value

P-value = P(Z < z)

P-value = P(Z< -2.30)

By using the P-value method and the normal distribution as an approximation to the binomial distribution.

from the table of standard normal distribution

move left until the first column is reached. Note the value as –2.0

move upward until the top row is reached. Note the value as 0.30

find the probability value as 0.010724 by the intersection of the row and column values gives the area to the left of

z = -2.30

P- value = 2P(z ≤ -2.30)

P-value = 2 × 0.01072

P - value = 0.02144

Decision Rule: Since the p-value is lesser than the level of significance; then we reject the null hypothesis.

Conclusion: We accept the alternative hypothesis and conclude that under the same circumstances the proportion of offspring peas will be yellow is not equal to 0.27

8 0

3 years ago

>><br> What is the value of x that makes PQ|| RS?<br> plssss help. i need help bad

kirill [66]

Answer: 55

Step-by-step explanation:

By the alternate exterior angles theorem,

$3x-65=2x-10\\x-65=-10\\x=55$

5 0

2 years ago

shepuryov [24]

Answer:

The two odd numbers are 15 and 17

Step-by-step explanation:

Given

<em>Let the odd numbers be represented with x and y</em>

<em>Let x be the greater number</em>

<em></em> $x + 5y = 92$ <em></em>

<em></em>

<em>Required</em>

Find x and y

Since x and y are consecutive odd numbers and x is greater, then

$x = y + 2$

Substitute y + 2 for x in $x + 5y = 92$ <em></em>

<em></em> $y + 2 + 5y = 92$ <em></em>

<em></em>

Collect Like Terms

<em></em> $y + 5y = 92 - 2$ <em></em>

<em></em> $6y = 90$ <em></em>

Divide both sides by 6

$\frac{6y}{6} = \frac{90}{6}$

$y = \frac{90}{6}$

$y = 15$

Substitute 15 for y in $x = y + 2$

$x = 15 + 2$

$x = 17$

<em>Hence; the two odd numbers are 15 and 17</em>

4 0

3 years ago