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3 years ago

Whats the answer for number 3

Mathematics

1 answer:

Karolina [17]3 years ago

5 0

cant see the full question ;/

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How can you use the number of inches in one foot to find the number of square inches in one square foot?

d1i1m1o1n [39]

There are 12 inches in 1 foot. You know that the area of a square is or base times hight. A square has the same base and height. So we can say (base)^2. If the base is 12 inches in this case 12^2 = 144. Answer: 144 square inches.

8 0

3 years ago

£360 is shared between Abby, ben, chloe and denesh. the ratio of the amount abby gets to the amount that ben gets is 2:7. chloe

Gwar [14]

Answer:

$210$ £

Step-by-step explanation:

Let amount that abby gets $=x$

Given that $\frac{Amount\ of\ abby}{Amount\ of\ Ben} =\frac{2}{7}$

$Amount\ of\ ben=\frac{7}{2}\times Amount\ of\ abby\\ =\frac{7}{2}\ x$

Amount of chole + amount of Danesh $=1.5\times$ of abby

$=1.5 \ x$

$x +\frac{7}{2} \ x + 1.5 \ x =360\\\\6x=360\\\\x=\frac{360}{6}\\\\x=60$

$Amount\ of\ Ben =\frac{7}{2}\ x = \frac{7}{2} \times 60\\\\=7\times 30\\\\=210$

6 0

3 years ago

An instructor gives her class the choice to do 7 questions out of the 10 on an exam.

Maksim231197 [3]

Answer:

(a) 120 choices

(b) 110 choices

Step-by-step explanation:

The number of ways in which we can select k element from a group n elements is given by:

$nCk=\frac{n!}{k!(n-k)!}$

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

$10C7=\frac{10!}{7!(10-7)!}=120$

Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

$(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50$

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

$(5C4)(5C3)=\frac{5!}{4!(5-4)!}*\frac{5!}{3!(5-3)!}=50$

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

$(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10$