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Vladimir79 [104]
3 years ago
12

Taylor has nickels and dimes. The number of nickels is 7 less then eight times the number of dimes. If d represents the number o

f dimes then the number of nickels can be expressed as what
Mathematics
1 answer:
svp [43]3 years ago
4 0

Answer: 8d-7

Step-by-step explanation:

Given

Taylor has nickels and dimes

Number of nickels is 7 less than eight times the number of dimes

If d is the number of dimes, then number of nickels is given by

\Rightarrow \text{Number of Nickels = }8d-7

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Alexandra [31]
<h2>Answer:</h2>

a. <-13/2,-13/2>

<h2>Step-by-step explanation:</h2>

The projection of a vector u onto another vector v is given by;

proj_vu = (\frac{u.v}{|v|^2})v               ----------------(i)

Where;

u.v is the dot product of vectors u and v

|v| is the magnitude of vector v

Given:

u = <-6, -7>

v = <1, 1>

These can be re-written in unit vector notation as;

u = -6i -7j

v = i + j

<em>Now;</em>

<em>Let's find the following</em>

(i) u . v

u . v = (-6i - 7j) . (i + j)

u . v = (-6i) (1i) + (-7j)(1j)          [Remember that, i.i = j.j = 1]

u . v = -6 -7 = -13

(ii) |v|

|v| = \sqrt{(1)^2 + (1)^2}

|v| = \sqrt{2}

<em>Substitute these values into equation (i) as follows;</em>

proj_vu = [\frac{-13}{(\sqrt{2}) ^2}][i + j]

proj_vu = \frac{-13}{2} [i + j]

This can be re-written as;

proj_vu = \frac{-13}{2}i + \frac{-13}{2}j

proj_vu =

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The value of x in the equation illustrated is 3/4.

<h3>How to illustrate the information?</h3>

It should be noted that the function that's given based on the information is illustrated as:

x³ = 27/64

It should be noted that in this case, it is important to cube root 27/64 to be able to get the value.

This will be:

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