Answer:elements cannot be split into two
Explanation:elements are pure substances which cannot be split into two by chemical means
Answer:
Equilibrium concentration of Br₂ = 0.02 M
Explanation:
Moles of hydrogen gas :
Given, Mass of H₂ = 1.374 g
Molar mass of H₂ = 2.016 g/mol
The formula for the calculation of moles is shown below:
Thus,
Moles of Bromine gas :
Given, Mass of Br₂ = 70.31 g
Molar mass of Br₂ = 159.808 g/mol
The formula for the calculation of moles is shown below:
Thus,
Considering the ICE table for the equilibrium as:
H₂(g) + Br₂(g) ⇌ 2HBr(g)
t = o 0.68 0.44 0
t = eq -x -x +2x
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Moles at eq: 0.68-x 0.44-x 2x
Given that: At equilibrium the vessel is found to contain 0.566 g of H₂
Moles = 0.566 g / 2.016 g/mol = 0.28 moles
Thus, 0.68 - x = 0.28
x = 0.40 moles
Volume = 2.00 L
Equilibrium moles of Br₂ = 0.44 - 0.40 moles = 0.04 moles
<u>Equilibrium concentration of Br₂ = 0.04 moles/ 2 L = 0.02 M</u>
Answer:
Theoretical yield: 13.9 g
Percent yield: 94 %
Explanation:
The reaction is:
CaCO₃ → CaO + CO₂
We see that the reaction is correctly balanced.
1 mol of calcium carbonate can decompose to 1 mol of calcium oxide and 1 mol of carbon dioxide.
We convert the mass to moles: 24.8 g . 1mol / 100.08g = 0.248 moles
As ratio is 1:1, 0.248 moles of salt can decompose to 1 mol of oxide.
We convert the moles to mass: 0.248 mol . 56.08g /1mol = 13.9 g
That's the theoretical yield.
To determine the percent yield we think:
(Determined yield / Theoretical yield) . 100 → (13.1 / 13.9) . 100 = 94 %
Answer:
52,000 kJ
Explanation:
The combustion reaction is the following:
2 C₂H₆(g) + 7 O₂(g) → 4CO₂(g) + 6H₂O(l) ΔHm= –3120 kJ
From the chemical reaction and the value of ΔH we can see that 2 moles of ethane gas (C₂H₆(g)) release 3120 kJ of heat energy. So, we have the conversion factor: 3120 kJ/2 moles C₂H₆.
To calculate how many kJ are released from the combustion of 1 kg of ethane, we have to first convert the mass to moles by using the molecular weight (MW) of ethane (C₂H₆):
MW(C₂H₆) = (12 g/mol x 2 C) + (1 g/mol x 6 H) = 30 g/mol
mass = 1 kg x 1000 g/1 kg = 1000 g
moles of C₂H₆= mass/MW = 1000 g/(30 g/mol) = 33.3 mol C₂H₆
Finally, we multiply the conversion factor by the number of moles of C₂H₆ in 1 kg:
heat energy released = 33.3 mol C₂H₆ x 3120 kJ/2 moles C₂H₆ = 52,000 kJ
Therefore, 51,000 kJ are released when 1 kg of ethane is burned.
Answer:
From the negative terminal of the battery to the positive one
Explanation:
DC is just dirrect current that has e- flowing from the negative terminal to the positive.
