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Anarel [89]
3 years ago
5

An erlenmeyer flask contains 15.00mL of 0.030 M HCI before titration. 5.00 mL of 0.050 of M NaOH is added to the HCI in the flas

k during titration. What is the mole ratio of acid (HCI) to base (NaOH) in the balanced neutralization equation?
0.05 to 0.03
1:1
1:2

which expression. gives the actual moles of base added?
0.050x5.00
0.030x0.015
0.050x0.005

How many moles of H+ will be present following neautralization?
0.25
0.00025
0.025​
Chemistry
1 answer:
e-lub [12.9K]3 years ago
8 0

Answer:

1.1

0.050*0.005

0.00025

Explanation:

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An atom with an atomic number of 18 will have how many electrons in its innermost orbit
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Answer:

2 electrons

Explanation:

The K shell is the innermost orbit and it contains 2 electrons

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POS MOLECULES SPEED UP WHEN ENERGY IS CREATED AND SLOW DOWN WHEN ENERGY IS DESTROYED True False? explain why​
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3 years ago
Identify the correct coefficients to balance the redox reaction with the lowest possible integer coefficients.
Monica [59]

Answer:

\rm 3\; Ag^{1+} + 1\; Al \to 1\; Al^{3+} + 3\; Ag.

Explanation:

Electrons are conserved in a chemical equation.

The superscript of \rm Ag^{1+} indicates that each of these ions carries a charge of +1. That corresponds to the shortage of one electron for each \rm Ag^{+} ion.

Similarly, the superscript +3 on each \rm Al^{3+} ion indicates a shortage of three electrons per such ion.

Assume that the coefficient of \rm Ag^{+} (among the reactants) is x, and that the coefficient of \rm Al^{3+} (among the reactants) is y.

\rm \mathnormal{x}\; Ag^{1+} + ?\; Al \to \mathnormal{y}\; Al^{3+} + ?\; Ag.

There would thus be x silver (\rm Ag) atoms and y aluminum (\rm Al) atoms on either side of the equation. Hence, the coefficient for \rm Al\! and \rm Ag\! would be y\! and x\!, respectively.

\rm \mathnormal{x}\; Ag^{1+} + \mathnormal{y}\; Al \to \mathnormal{y}\; Al^{3+} + \mathnormal{x}\; Ag.

The x \rm Ag^{1+} ions on the left-hand side of the equation would correspond to the shortage of x electrons. On the other hand, the y Al^{3+} ions on the right-hand side of this equation would correspond to the shortage of 3\, y electrons.

Just like atoms, electrons are also conserved in a chemical reaction. Therefore, if the left-hand side has a shortage of x electrons, the right-hand side should also be x\! electrons short of being neutral. On the other hand, it is already shown that the right-hand side would have a shortage of 3\, y electrons. These two expressions should have the same value. Therefore, x = 3\, y.

The smallest integer x and y that could satisfy this relation are x = 3 and y = 1. The equation becomes:

\rm 3\; Ag^{1+} + 1\; Al \to 1\; Al^{3+} + 3\; Ag.

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