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Volgvan
4 years ago
5

Which ordered pair in the form X Y is a solution of this equation (x+6)y=9​

Mathematics
2 answers:
Ghella [55]4 years ago
8 0

Answer:

The system has infinitely many solutions

Step-by-step explanation:

zimovet [89]4 years ago
6 0

when x=3 then y=1

when x=6 then y=-3

HOPE THIS WILL HELP U

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At a certain college, 28% of the students major in engineering, 18% play club sports, and 8% both major in engineering and play
Alex

Answers: 0.286

Explanation:

Let E → major in Engineering

Let S → Play club sports

P (E) = 28% = 0.28

P (S) = 18% = 0.18

P (E ∩ S ) = 8% = 0.08

Probability of student plays club sports given majoring in engineering,

P ( S | E ) = P (E ∩ S ) ÷ P (E) = 0.08 ÷ 0.28 = 0.286

8 0
3 years ago
Given that
Pepsi [2]

Answer:

The answer would have to be 76

Step-by-step explanation:

5 0
3 years ago
The costs of different weights of onions sold at a grocery store are shown in the table
lana66690 [7]

Answer:

<h2>Independent variable: Weight of Onions.</h2><h2>Dependent variable: Total Cost.</h2>

Step-by-step explanation:

The given table is about the weight of onions in pounds and the total cost.

If you think this through, you would notice that the total cost depends on the number of pounds of onions. That means the independent variable is Weight of Onions and the dependent variable is the Total Cost.

So, to put it in a sentence: The weight of onions determines the total cost.

8 0
3 years ago
Read 2 more answers
URGENTE, PERGUNTAS DE MARCAR:
Norma-Jean [14]

Answer:

2a: (c)

5o: (1, 3) and (1,1)

3a: (b)

1a: (d)

4o: (b)

Step-by-step explanation:

2a: the equation of a circle circumference needs to be transformable to the form (x-x_C)^2 + (y - y_C)^2 = r^2 where C(x_C; y_C) is the center and <em>r</em> is the radius. (a) and (d) can’t be it because they contain non-zero factors on <em>xy</em>. (b) isn’t an equation.

5o: just put the given (<em>x</em>, <em>y</em>) into the equations and see if it holds. (2, 3) isn’t on the circumference of (1) because 2^2+3^2-2\cdot 2 -4\cdot 3 + 4 = 1 \neq 0, (3, 1) isn’t on it either because 3^2 + 1^2 - 2\cdot 3 - 4\cdot 1 + 4 = 4 \neq 0.

3a: calculate the value of the left-hand side term of the equation using (<em>x</em>, <em>y</em>) from the given point <em>M</em>. That’s the difference of square distance to the center to the square radius r^2. Thus it’s 0 if the point is on the circumference, negative if inside and positive if outside. You get 3^2 + 4^2 - 6\cdot 3 -2\cdot 4 + 8 = 7, positive, so it’s outside the circle.

1a: see definition from 2a. Here, r^2 = 9.

4o: insert the y from the straight line equation (r) (which can be equivalently transformed to y = x+1) into the circumference equation. If it yields no solution, that’s outside, it there’s exactly one solution, that’s a tangent and if there are two solutions, it’s a secant. x^2+(x+1)^2+2x - 4(x+1) = x^2 + x^2 + 2x + 1  + 2x - 4x + 4 = 2x^2 + 5 = 0 \iff x^2 = 2.5 \iff x \in \{-\sqrt{2.5}, \sqrt{2.5}\} There are two solutions, so it’s a secant.

3 0
3 years ago
Factor the expression below 25x^2+20x+4
Leona [35]

Answer:

the correct answer is (5x+2)^2

6 0
3 years ago
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