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3 years ago

Which choice shows the coordinates of C’ if the trapezoid is reflected across the y-axis?

Mathematics

2 answers:

suter [353]3 years ago

6 0

A reflection through the axis and is given by the following transformation rule:
(x, y) -------> (-x, y)
We have the following point:
C = (5, 3)
Applying the transformation rule we have:
(5, 3) -------> (-5, 3)
Therefore, C' is given by:
C '= (- 5, 3)
Answer:
(-5, 3)

Sergeeva-Olga [200]3 years ago

5 0

Answer:

A) (-5, 3)

Step-by-step explanation:

The coordinate of C is (5, 3).

The trapezoid is reflected across the y-axis.

(x, y ) ----> (-x, y)

When it is reflected over y-axis only the sign of the x coordinate change and y coordinate remains the same.

Therefore, (5, 3) --->(-5, 3)

C' = (-5, 3)

Answer: A) (-5, 3)

Hope this will helpful.

Thank you.

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A ferry is travelling at a constant speed back to the dock, as shown in the graph. Which

mario62 [17]

Answer:

c. y = -35*x + 105

Step-by-step explanation:

Lo que demos hacer es calcular los puntos cuando x = 0 y cuando x = 3, es decir el inicio y el fin del recorrido.

Cuando x es igual 0, y = 105, por lo tanto, la función sería:

y = A*x + 105

Cuando x = 3, y = 0, por lo tanto:

0 = 3*A + 105

resolvemos para A:

3*A = -105

A = -105/3

A = -35

Por lo tanto la función es:

y = -35*x + 105

es decir, la opción c.

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2 years ago

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The random variable X is exponentially distributed, where X represents the waiting time to be seated at a restaurant during the

erastova [34]

Answer:

The probability that the wait time is greater than 14 minutes is 0.4786.

Step-by-step explanation:

The random variable X is defined as the waiting time to be seated at a restaurant during the evening.

The average waiting time is, β = 19 minutes.

The random variable X follows an Exponential distribution with parameter $\lambda=\frac{1}{\beta}=\frac{1}{19}$ .

The probability distribution function of X is:

$f(x)=\lambda e^{-\lambda x};\ x=0,1,2,3...$

Compute the value of the event (X > 14) as follows:

$P(X>14)=\int\limits^{\infty}_{14} {\lambda e^{-\lambda x}} \, dx=\lambda \int\limits^{\infty}_{14} {e^{-\lambda x}} \, dx\\=\lambda |\frac{e^{-\lambda x}}{-\lambda}|^{\infty}_{14}=e^{-\frac{1}{19} \times14}-0\\=0.4786$

Thus, the probability that the wait time is greater than 14 minutes is 0.4786.

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2 years ago