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Nikitich [7]
4 years ago
12

Which choice shows the coordinates of C’ if the trapezoid is reflected across the y-axis?

Mathematics
2 answers:
suter [353]4 years ago
6 0
A reflection through the axis and is given by the following transformation rule:
 (x, y) -------> (-x, y)
 We have the following point:
 C = (5, 3)
 Applying the transformation rule we have:
 (5, 3) -------> (-5, 3)
 Therefore, C' is given by:
 C '= (- 5, 3)
 Answer:
 (-5, 3)
Sergeeva-Olga [200]4 years ago
5 0

Answer:

A) (-5, 3)

Step-by-step explanation:

The coordinate of C is (5, 3).

The trapezoid is reflected across the y-axis.

(x, y ) ----> (-x, y)

When it is reflected over y-axis only the sign of the x coordinate change and y coordinate remains the same.

Therefore, (5, 3) --->(-5, 3)

C' = (-5, 3)

Answer: A) (-5, 3)

Hope this will helpful.

Thank you.

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What is 0.0728 correct to two significant figures?
katen-ka-za [31]
0.073.

2SF is 2 numbers excluding preliminary zeros,

In this case you look at the third digit, 8, and then round up to 0.073.

:)
3 0
3 years ago
Volunteers for a political campaign gave out 21/38 of their fliers. They gave out the remaining 612 fliers in another neighborho
dmitriy555 [2]

The volunteers gave 1368 fliers in total.

Step-by-step explanation:

Given,

Fliers given by volunteers in first neighborhood = \frac{21}{38}

Remaining fliers = 612

Fraction of remaining fliers = 1-\frac{21}{38}=\frac{38-21}{38}

Fraction of remaining fliers = \frac{17}{38}

Let,

x be the total fliers given by volunteers.

\frac{17}{38}\ of\ x=612

\frac{17}{38}x=612

Multiplying both sides by \frac{38}{17}

\frac{38}{17}*\frac{17}{38}x=612*\frac{38}{17}\\\\x=\frac{23256}{17}\\\\x=1368

The volunteers gave 1368 fliers in total.

Keywords: fraction, division

Learn more about fractions at:

  • brainly.com/question/3126500
  • brainly.com/question/3306327

#LearnwithBrainly

4 0
3 years ago
I'm sorry but these are the multiple choice answers.
Sunny_sXe [5.5K]
\bf \qquad \qquad \textit{Future Value of an ordinary annuity}
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]


\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{original amount}\\
\textit{already compounded}
\end{array}&
\begin{array}{llll}

\end{array}\\
pymnt=\textit{periodic payments}\to &200\\
r=rate\to 7\%\to \frac{7}{100}\to &0.07\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, four quarters}
\end{array}\to &4\\

t=years\to &12
\end{cases}
\\\\\\
A=200\left[ \cfrac{\left( 1+\frac{0.07}{4} \right)^{4\cdot 12}-1}{\frac{0.07}{4}} \right]
7 0
3 years ago
Which value of x makes this equation true? 100-6x =160-10x
Verdich [7]

Answer:

x=15

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
6x+3x-(x-10)=20x help... step by step.
mihalych1998 [28]
In equations we always want to do the same thing to both sides so the equation stays equal

in an equation with one unknown (x) we try to get the unknown on one side

so -(x-10)
this means that you multiply everything in the equation by -1 or in other words you make everything in the parenthasees the opposite sign of what it is so

6x+3x-x+10=20x
add like terms
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6 0
3 years ago
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