Answer:
The ball will reach a height of 5 ft by the 4th time.
Step-by-step explanation:
The initial height of the ball is 40 ft, when it bounces from the floor once the height will be 20 ft, the second time it'll be 10 ft, and so on. The sequence that can represent the maximum height of the ball after each bounce is:
{40, 20, 10,...}
This kind of sequence is called a geometric progression, in this kind of progression the next number is related to the one before it by the product of a constant called ratio, in this case 1/2. To calculate a specific position in this sequence we only need the ratio and the first number, using the formula below:
a_n = a*r^(n-1)
Where n is the position we want to know, a is the first number and r is the ratio. In this case we have:
a_4 = 40*(1/2)^(4-1) = 40*(1/2)^3 = 40/8 = 5
The ball will reach a height of 5 ft by the 4th time.
Answer:
Step-by-step explanation:
we know that
so solve for x
<u>Answer:</u>
Planet A is inner
Planet A is Mars
Planet B is Outer
Planet B is Uranus
<u>Solution:</u>
We know that the inner planets are the planets which are close to the sun. They are relatively small, mostly rocky composition, and have few or no moons.
On other hand, the outer planets are the planets which are far away from the sun. They are mostly huge, ringed, gaseous and have several moons.
In the given problem,
Planet A has rocky mantle and iron core, less no of Moons and no rings, also due to 96% of carbon dioxide, 3% nitrogen and 1% other gases this is denser, and Hence Planet A is inner planet. As the distance from the sun is 1.5 AU and no of moons are 2, hence Planet A is Mars.
On the other hand, Planet B is gaseous with hydrogen and helium gas, hence it is also denser and it has large no of moons and faint rings. So Planet B is Outer planet. As the distance of the planet is 19.22 AU and has 27 moons, hence Planet B is Uranus.
