Answer:
Yes, an arrow can be drawn from 10.3 so the relation is a function.
Step-by-step explanation:
Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.
The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.
In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.
However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.
F(x)=5x-2
y=5x-2
y=5(3)-2
y=15-2
y=13
so the answer is B. 13
Answer:
reverse
Step-by-step explanation:
When you multiply or divide on one side of an inequaltiy, you have to mirror it on the other side and you have to reverse the inequality sign.
Answer:
Mean-6.3 (3 repeating)
Median-5
Mode-1
Step-by-step explanation:
Mean-Add all numbers together and divide by 12 (because is 12 numbers)
Median- List numbers From least to greatest and cross one off of each end until you meet in the middle
Mode- find the number that occurs the most
Answer: C
<u>Step-by-step explanation:</u>
Use the multiplication rule for matrices - Multiply 1st row of first matrix with 1st column of second matrix and find their sum. Repeat for each row and column.
A x B
![\left[\begin{array}{cc}1&5\\-3&4\end{array}\right] \times \left[\begin{array}{cc}2&6\\6&-1\end{array}\right]=\left[\begin{array}{cc}1(2)+5(6)&1(6)+5(-1)\\-3(2)+4(6)&-3(6)+4(-1)\end{array}\right]\\\\\\.\qquad \qquad \qquad \qquad \qquad \quad =\left[\begin{array}{cc}32&1\\18&-22\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%265%5C%5C-3%264%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%266%5C%5C6%26-1%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%282%29%2B5%286%29%261%286%29%2B5%28-1%29%5C%5C-3%282%29%2B4%286%29%26-3%286%29%2B4%28-1%29%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5C%5C%5C.%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cquad%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D32%261%5C%5C18%26-22%5Cend%7Barray%7D%5Cright%5D)