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2 years ago

Solve the equation. 5y - 10 = -25

Mathematics

3 answers:

algol [13]2 years ago

8 0

Answer: 5y-10= -25

5y -10+10= -25 +10

Step-by-step explanation:

mixas84 [53]2 years ago

8 0

Answer:

Y= (-3)

Step-by-step explanation:

(5)(-3)= -15

-15-10= -25

Y= -3

Jgunnels172 years ago

0 0

y=-3 is ur answer.

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Shalnov [3]

Answer:

i6 sqrt 5

Step-by-step explanation:

It cannot be 12i sqrt 5 as this is 26.8326....

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2 years ago

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What is the altitude of the equilateral triangle?

MAXImum [283]

It’s not going to be C because 10 is already in the question

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3 years ago

HELP PLEASE: Which is the equation of the graphed line written in

maksim [4K]

Answer:

$x - y = 0$

Step-by-step explanation:

Required

The graph equation

From the graph, we have:

$(x_1,y_1) = (0,0)$

$(x_2,y_2) = (1,1)$

The slope of the graph is:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{1-0}{1-0}$

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$m =1$

So, the graph equation is:

$y = m(x - x_1) + y_1$

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In standard form, we have:

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3 years ago

Consider the following. f(x) = x5 − x3 + 6, −1 ≤ x ≤ 1 (a) Use a graph to find the absolute maximum and minimum values of the fu

kykrilka [37]

ANSWER

See below

EXPLANATION

Part a)

The given function is

$f(x) = {x}^{5} - {x}^{3} + 6$

From the graph, we can observe that, the absolute maximum occurs at (-0.7746,6.1859) and the absolute minimum occurs at (0.7746,5.8141).

b) Using calculus, we find the first derivative of the given function.

$f'(x) = 5 {x}^{4} - 3 {x}^{2}$

At turning point f'(x)=0.

$5 {x}^{4} - 3 {x}^{2} = 0$

This implies that,

${x}^{2} (5 {x}^{2} - 3) = 0$

${x}^{2} = 0 \: or \: 5 {x}^{2} - 3 = 0$

$x = - \frac{ \sqrt{15} }{5} \: or \: x = 0 \: \: or \: x =\frac{ \sqrt{15} }{5}$

We plug this values into the original function to obtain the y-values of the turning points

$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} +750)) \:and \: (0, - 6) \: and\: ( \frac{ \sqrt{15} }{5} , \frac{1}{125} ( - 6 \sqrt{15} +750))$

We now use the second derivative test to determine the absolute maximum minimum on the interval [-1,1]

$f''(x) = 20 {x}^{3} - 6x$

$f''( - \frac{ \sqrt{15} }{5} ) \: < \: 0$

Hence

$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} + 750))$

is a maximum point.

$f''( \frac{ \sqrt{15} }{5} ) \: > \: 0$

Hence

$( \frac{ \sqrt{15} }{5} , \frac{1}{125} (- 6 \sqrt{15} + 750))$

is a minimum point.

$f''(0) \: =\: 0$

Hence (0,-6) is a point of inflexion

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3 years ago

Who needs pts.<br> Look for my next question... ill be giving a free 100pts

IRISSAK [1]

Answer:

Step-by-step explanation:

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3 years ago

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