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labwork [276]
2 years ago
5

Solve the equation. 5y - 10 = -25

Mathematics
3 answers:
algol [13]2 years ago
8 0

Answer: 5y-10= -25

5y -10+10= -25 +10

Step-by-step explanation:

mixas84 [53]2 years ago
8 0

Answer:

Y= (-3)

Step-by-step explanation:

(5)(-3)= -15

-15-10= -25

Y= -3

Jgunnels172 years ago
0 0

y=-3 is ur answer.

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3 is How many hours they spent in the parking lot.
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Which of the given is the set of zeroes of the polynomial p(x)=2x3+x2-5x+2
velikii [3]
-2, 1/2, 1



Simplify down all the way and get your answer



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What is the recursive rule for the sequence 2, -1, 1/2 , -1/4
Helga [31]

Answer:

a_n=\frac{-1}{2}a_{n-1}

a_1=2

Step-by-step explanation:

The recursive rule is a term defined in terms of other terms in the sequence.

The is a geometric sequence because it has a common ratio.

The common ratio can be found by dividing a term by previous term.

For example, all of these are equal:

\frac{-1}{2}

\frac{\frac{1}{2}}{-1}

\frac{\frac{-1}{4}}{\frac{1}{2}}

They are all equal to \frac{-1}{2}.

So we are saying:

\frac{\text{term}}{\text{previous term}}}=\frac{-1}{2}

More formally:

\frac{a_n}{a_{n-1}}=\frac{-1}{2}.

Multiply both sides by a_{n-1}:

a_n=\frac{-1}{2}a_{n-1}

When doing recursive form, you need to state a term of the sequence (or more depending on the recursive form you have).

So the first term is 2.

So the full thing for the answer is:

a_n=\frac{-1}{2}a_{n-1}

a_1=2

8 0
3 years ago
The diameter of a circle has length 12. The center is at*(-5, 2). Give the equation
labwork [276]

Answer:

Equation of the circle is : x^{2} + 10x + y^{2} -4y -7 =0

Step-by-step explanation:

Let us consider the image attached in the answer area.

The center<em> O</em> has the co-ordinates i.e. <em>(-5,2)</em> and the diameter given is <em>12 units</em>.

We know that radius is half of diameter.

\text{Radius = }\dfrac{\text{Diameter}}{2}

\text{Radius = }\dfrac{12}{2}\\\Rightarrow \text{Radius = 6units}

The equation for circle given the center and radius, can be represented as:

(x-a)^{2}+ (y-b)^{2} = r^{2}

Where <em>(a,b)</em> is the co-ordinate of center and <em>r</em> is the radius.

Let us consider the following formula:

(p+q)^2 = p^{2}+ q^{2} +2pq\\(p-q)^2 = p^{2}+ q^{2} -2pq

(x-(-5))^{2}+ (y-2)^{2} = 6^{2}\\\Rightarrow (x+5)^{2}+ (y-2)^{2} = 36\\\Rightarrow x^{2} + 25 + 10x +y^{2} + 4-4y=36\\\Rightarrow x^{2} + 10x +y^{2} -4y-7=0

Hence, Equation of the circle is : x^{2} + 10x + y^{2} -4y -7 =0

4 0
3 years ago
Select all irrational numbers.
balu736 [363]

Answer:

B C F

Step-by-step explanation:

If you reduce those answer and try to find the square roots, the decimals are terminating and never ending, while the others are perfect squares.

6 0
3 years ago
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