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3 years ago

5

I NEED HELP !!!!!!!!!

1 answer:

marissa [1.9K]3 years ago

7 0

Answer:

b

d

e

Step-by-step explanation:

the standar form is

$ax^{2} +bx+c=0$

so it's

$0.5x^{2} -3.2x+5.8=0\\\\-x^2-3x+20=0\\\\\frac{1}{2}x^2+4x-3=0\\\\$

only that

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У= 3х-5<br> у = 3х+12<br> Please help ASAP for my lil sister

exis [7]

Answer:

0

Step-by-step explanation:

The equation is undefined.

4 0

3 years ago

What is a factor of -270 that adds to be -39

sergeinik [125]

For this one your answer is -309

4 0

3 years ago

Use the Ratio Test to determine the convergence or divergence of the series. If the Ratio Test is inconclusive, determine the co

jeka57 [31]

Answer:

<h2>A. The series CONVERGES</h2>

Step-by-step explanation:

If $\sum a_n$ is a series, for the series to converge/diverge according to ratio test, the following conditions must be met.

$\lim_{n \to \infty} |\frac{a_n_+_1}{a_n}| = \rho$

If $\rho$ < 1, the series converges absolutely

If $\rho > 1$ , the series diverges

If $\rho = 1$ , the test fails.

Given the series $\sum\left\ {\infty} \atop {1} \right \frac{n^2}{5^n}$

To test for convergence or divergence using ratio test, we will use the condition above.

$a_n = \frac{n^2}{5^n} \\a_n_+_1 = \frac{(n+1)^2}{5^{n+1}}$

$\frac{a_n_+_1}{a_n} = \frac{{\frac{(n+1)^2}{5^{n+1}}}}{\frac{n^2}{5^n} }\\\\ \frac{a_n_+_1}{a_n} = {{\frac{(n+1)^2}{5^{n+1}} * \frac{5^n}{n^2}\$

$\frac{a_n_+_1}{a_n} = {{\frac{(n^2+2n+1)}{5^n*5^1}} * \frac{5^n}{n^2}\\$

aₙ₊₁/aₙ =

$\lim_{n \to \infty} |\frac{ n^2+2n+1}{5n^2}| \\\\Dividing\ through\ by \ n^2\\\\\lim_{n \to \infty} |\frac{ n^2/n^2+2n/n^2+1/n^2}{5n^2/n^2}|\\\\\lim_{n \to \infty} |\frac{1+2/n+1/n^2}{5}|\\\\$

note that any constant dividing infinity is equal to zero

$|\frac{1+2/\infty+1/\infty^2}{5}|\\\\$

$\frac{1+0+0}{5}\\ = 1/5$

$\rho = 1/5$

Since The limit of the sequence given is less than 1, hence the series converges.

5 0

3 years ago

1. determine if the functions are inverse functions

kirill115 [55]

Answer:

<u>Question 1</u>

The function $f(x) = x + 6$ is one-to-one, so it does have an inverse.

The inverse of +6 is -6, so $f^{-1}(x)=x-6$

Therefore, g(x) is the inverse of f(x).

<u>Question 2</u>

The function $f(x) = -3x -9$ is one-to-one, so it does have an inverse.

To find the inverse, replace f(x) with y:

$\implies y = -3x -9$

Rearrange the equation to make x the subject:

$\implies y+9= -3x$

$\implies x=-\dfrac13(y+9)$

$\implies x=-\dfrac13y-3$

Replace x with $f^{-1}(x)$ and y with x:

$\implies f^{-1}(x)=-\dfrac13x-3$

Therefore, g(x) is the inverse of f(x).

5 0

2 years ago

Please help the questions are in the picture above

svp [43]

Not sure if I'm right but I think it's 3(x - 6) (x^2 + 5x)

Step-by-step explanation:

3x^3 - 3x^2 - 90x

Apply GCF: 3 (x^3 - x^2 - 30)

Split 30 into -6 and 5

(x^3 - 6x^2) (5x^2 - 30x)

GCF of both: x^2 (x - 6) and 5x (x - 6)

DON'T FORGET TO CARRY THE 3

And your answer is 3 (x - 6) (x^2 + 5x)

5 0

3 years ago