Answer:
Step-by-step explanation:
In the division algorithm, if the remainder is zero, then the algorithm terminates, resulting in a terminating decimal. remainder repeats, the calculations that follow will also repeat in a cyclical pattern causing a repeating decimal.
Answer: Option C.
Step-by-step explanation:
The data is:
Destin walked 2km
Jane walked 4000ft.
Let's write both of those in the same units.
The data given is:
1ft = 0.0003048km.
and 4000ft is 4000 times that:
4000ft = 4000*1ft = 4000*0.0003048km = 1.22km
Then if we add those, we get:
Total distance = 2km + 1.22km = 3.22km
So we can already discard option D.
Now, we know that:
1km = 0.6214 miles.
then 3.22 km is 3.22 times that amount:
3.22km = 3.22*1km = 3.22*(0.6214 mi) = 2 miles
The correct option is C.
9514 1404 393
Answer:
14.01, 493, 87
Step-by-step explanation:
Subtracting 28 from both sides tells you the range of values you need to be looking at.
28 + x > 42
x > 14
Any values more than 14 will make the inequality true. Three of them are ...
14.01, 493, 87
9514 1404 393
Answer:
-3 ≤ x ≤ 19/3
Step-by-step explanation:
This inequality can be resolved to a compound inequality:
-7 ≤ (3x -5)/2 ≤ 7
Multiply all parts by 2.
-14 ≤ 3x -5 ≤ 14
Add 5 to all parts.
-9 ≤ 3x ≤ 19
Divide all parts by 3.
-3 ≤ x ≤ 19/3
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<em>Additional comment</em>
If you subtract 7 from both sides of the given inequality, it becomes ...
|(3x -5)/2| -7 ≤ 0
Then you're looking for the values of x that bound the region where the graph is below the x-axis. Those are shown in the attachment. For graphing purposes, I find this comparison to zero works well.
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For an algebraic solution, I like the compound inequality method shown above. That only works well when the inequality is of the form ...
|f(x)| < (some number) . . . . or ≤
If the inequality symbol points away from the absolute value expression, or if the (some number) expression involves the variable, then it is probably better to write the inequality in two parts with appropriate domain specifications:
|f(x)| > g(x) ⇒ f(x) > g(x) for f(x) > 0; or -f(x) > g(x) for f(x) < 0
Any solutions to these inequalities must respect their domains.
32x^2y
8xy^6
the gcf is 8xy