All categories

2 years ago

Why is 12 a composite number

Mathematics

2 answers:

Dennis_Churaev [7]2 years ago

7 0

A composite number has more than 2 factors<span>factors of 12 are:1x12, 2x6 3x4</span>

Gwar [14]2 years ago

5 0

Because it's a positive number that can be gained by multiplying two smaller positive numbers.

You might be interested in

Without graphing, classify the following system as independent, dependent, or inconsistent.

Galina-37 [17]

Answer:

Step-by-step explanation:

There is a missing operator in the second equation.

If the equation is 4x - 8y = 4, then the system is dependent. The second equation is a non-zero multiple of the first.

3 0

2 years ago

Hey, need help on this, What is 18.029 in expanded form?

Zigmanuir [339]

Answer:

The second one

Step-by-step explanation:

......................

4 0

2 years ago

Bernard designs motorized bicycles at Smart Gear Technologies. His total earnings are

olganol [36]

Answer: $43146

Step-by-step explanation:

So his total earning is $54,000. He has to pay $201 for every $1,000 he earns. So 54,000/1,000= 54. So now he has to pay 54*201=10854, 54000-10854=43146. His net income for this year is $43146.

8 0

2 years ago

What is the answer please.... need help

mina [271]

Answer:

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

$f\left(x\right)=x^3-6x^2+3x+10$

As the highest power of the x-variable is 3 with the leading coefficients of 1.

So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

$f\left(x\right)=x^3-6x^2+3x+10$

$0=x^3-6x^2+3x+10$ ∵ $f(x)=0$

$Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

$\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

if $ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x=-1,\:x=2,\:x=5$

Therefore, the zeros of the function are:

$x=-1,\:x=2,\:x=5$

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.

8 0

2 years ago

You are playing the game "Hidden Treasure" and your hint is that the treasure is 9 spaces away from the point (0, 0). Which of t

olganol [36]

Answer:

9,0 0,9 -9,0 0,-9

Step-by-step explanation:

up down left right

7 0

2 years ago