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Korolek [52]
3 years ago
11

Bills plant grew at the rate of 1 1/2. How tall would the plant be after 3 weeks

Mathematics
2 answers:
kvv77 [185]3 years ago
7 0

Answer:

9/2 or 4 1/2

Step-by-step explanation:

you do 1 1/2 times 3

3/2 times 3 equals

aev [14]3 years ago
6 0

Answer:

is it a day or week?

Step-by-step explanation:

week you would do 1 1/2*3

day you would do 1 1/2*21

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During the first 11 months of a recent year, a certain charitable organization received an average (arithmetic mean) of $20,600
Aleks04 [339]

Answer:

D. $25,400

Step-by-step explanation:

Let x represent the score during December.

We have been given that during 1 months of a recent year, a certain charitable organization received an average (arithmetic mean) of $20,600 per month in donations.

The total score for 11 months would be 11\times 20,600=226600.

We can set our given information in an equation as:

\text{Average}=\frac{\text{Sum of all data points}}{\text{Total number of data points}}

\frac{226,600+x}{12}=21,000

\frac{226,600+x}{12}*12=21,000*12

226,600+x=252,000

226,600-226,600+x=252,000-226,600

x=25,400

Therefore, the organization received $25,400 in donations during December and option D is the correct choice.

7 0
3 years ago
Write an equation for an ellipse centered at the origin, which has foci at (\pm5,0)(±5,0)(, plus minus, 5, comma, 0, )and vertic
Virty [35]

Answer:

The equation of ellipse is

\frac{x^2}{41}+\frac{y^2}{16}=1

Step-by-step explanation:

The equation of an ellipse is

\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1

where(h,k) is the center and c is distance from the center to the foci is given by a^2-b^2=c^2. a is the distance from the center to the vertices and b is the distance from the center to the co-vertices.

The center of the ellipse is the mid-point of the vertices.

The mid point of the vertices (\pm\sqrt{41},0) is

=(\frac{\sqrt{41}+(-\sqr{41})}2,\frac{0+0}2)

=(0,0)

a is the distance between the center and the vertices.

So, a=\sqrt{(0-\sqrt{41})^2+(0-0)^2}

        =\sqrt{41}

c is the distance between the center and the foci.

So, c=\sqrt{(0-5)^2+(0-0)^2

         =5

a^2-b^2=c^2

\Rightarrow (\sqrt41)^2-b^2=5^2

\Rightarrow b^2=(\sqrt41)^2- 5^2

\Rightarrow b^2=41-25

\Rightarrow b^2=16

The equation of ellipse is

\frac{(x-0)^2}{(\sqrt{41})^2}+\frac{(y-0)^2}{16}=1

\Rightarrow \frac{x^2}{41}+\frac{y^2}{16}=1

7 0
3 years ago
Write the expression with fewer terms. 10x-2x​
andreyandreev [35.5K]

Answer:

It would be 8x

Step-by-step explanation:

Since 10x and -2x are like terms, you can subtract -2x from 10x to get 8x.

10x - 2x = 8x

6 0
3 years ago
Read 2 more answers
I need the answer like asap
vfiekz [6]

Answer:

90 degrees?

Step-by-step explanation:

Angle KLM is 90 degrees

3 0
3 years ago
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Find a number t such that the line passing through the two points has slope -3.<br> (2, t); (-2, 3)
Alex
Change in x is 4, multiply that by slope, which is rise/run so you displace the y value by -3*4 or -12
t = -9

4 0
3 years ago
Read 2 more answers
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