The submarine is now 617.5 feet below sea level, or at -617.5 feet. the temperature is now at 65 9/20
you have to add the first values with the second values :)
Perimeter (P) = 2 · Length(L) + 2 · Width (W) → P = 2L + 2W
Solve for either L or W (I am solving for L).
200 - 2W = 2L
(200 - 2W)/2 = L
100 - W = L
Area (A) = Length (L) · Width (W)
= (100 - W) · W
= 100W - W²
Find the derivative, set it equal to 0, and solve:
dA/dW = 100 - 2W
0 = 100 - 2W
W = 50
refer to the equation above for L:
100 - W = L
100 - 50 = L
50 = L
Dimensions for the maximum Area are 50 ft x 50 ft
Step-by-step explanation:
evaluate
0
factor$2200/month
0
MV =MegaVolt (1 MV = 1000000 V)
KV = KiloVolt (1 KV = 1000 V)
V = Volt (1V = 1 V) :))
mV = miliVolt (1V = 1000 mV)
μV = microVolt (1V) = 1000000 μV
Answer:
t(n)=8n-4
Step-by-step explanation:
8 is the common difference and -4 is the 0th term.
