Order the set of numbers from least to greatest: negative 5 over 6, negative 5, negative square root 26, negative 31 over 6

Mathematics

2 answers:

Vikki [24]2 years ago

5 0

Answer:

Answer -31/6, - sqrt 26, -5, -5/6

julsineya [31]2 years ago

4 0

-5/6 = - 0.833
-5
- sqrt 26 = - 5.09
-31/6 = - 5.16

** negatives, unlike positive, the larger the number, the smaller it is

Least to greatest : -31/6, - sqrt 26, -5, -5/6

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If 1/8(8x+15)24, what is the value of x?

Lelechka [254]

Answer:

$x=22.125$ or $x=\frac{177}{8}$

Step-by-step explanation:

<u><em>The correct equation is</em></u>

$1/8(8x+15)=24$

solve for x

Multiply by 8 both sides to remove the fraction

$(8x+15)=192$

subtract 15 both sides

$8x=192-15\\8x=177$

divide by 8 both sides

$x=\frac{177}{8}$

$x=22.125$

3 0

2 years ago

Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$