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lisabon 2012 [21]
3 years ago
7

Solve the following system: y = 5x 3x + 2y = 52 Your answer:​

Mathematics
1 answer:
VashaNatasha [74]3 years ago
3 0
  • y = 5x ............. (i)
  • 3x + 2y = 52 ............ (ii)

After putting the value of y into the eq. (ii) ,

\sf 3x + 2 \times 5x = 52

\sf ⇒ \: 3x + 10x = 52

⇒ \sf13x = 52

\sf ⇒x = 4

After putting the value of x into the eq. (1)

\sf \: y = 5 \times 4

⇒ \sf  y = 20

Hence, the value of x is 4

& the value of y is 20.

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The table shows all the possible outcomes for spinning the pointer of the spinner with four equal sized sections labeled 1–4 and
vladimir1956 [14]

Answer:

12.5%

Step-by-step explanation:

There are two types of spinners here and the outcome of them is independent. That means

P(odd number,C) = P(odd number) * P(C)

There are two odd numbers out of four numbers in the first spinner. The chance of odd number will be:

P(odd) = 2/(2+2)= 1/2= 50%

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Then the chance will be:

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3 years ago
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Masteriza [31]

Answer:

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Step-by-step explanation:

- 3 {f}^{3}  +  \frac{1}{6} MB = D

Multiply through by 6 to eliminate the fraction

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Move - 18f³ to the right side of the equation

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MB = 6D + 18 {f}^{3}

Divide both sides by M to make B stand alone

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\frac{MB}{M}  =  \frac{6D + 18 {f}^{3} }{M}

We have the final answer as

B = \frac{6D + 18 {f}^{3} }{M}

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