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2 years ago

8

HELP PLEASE FAST Solve for x

2 answers:

Veronika [31]2 years ago

8 0

Step-by-step explanation:

x + 70° = 130° {exterior angle of a triangle is equal to the sum of two opposite interior angles}

x = 130° - 70°

x = 60°

Now for 2x = 2 * 60° = 120°

11Alexandr11 [23.1K]2 years ago

5 0

Answer:

$x^o+2x^o=180^o [Sum~of~angles~of~straight~line~is~180^o]\\or, 3x^o=180^o\\or, x = 60^o$

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Simplify by combining like terms -17+2(6x-1)+5

earnstyle [38]

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Start with the original expression.

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Use the Distributive Property — multiply $2$ by both $6x$ and $-1$ .

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Combine the like terms — add up all the constants.

$-14+12x$

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3 years ago

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Your cell phone company charges $20 per month for 500 minutes plus an additional

Alex_Xolod [135]

Answer:

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2 years ago

A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.

noname [10]

Answer:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

Step-by-step explanation:

Given

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$L = 2W$

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$Sides\ Cost = \$6/ft^2$

Required

The dimension that minimizes the cost

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$Volume = LWH$

This gives:

$128 = LWH$

Substitute $L = 2W$

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$128 = 2W^2H$

Make H the subject

$H = \frac{128}{2W^2}$

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The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

$A = LW + 2(WH + LH)$

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$Cost = 9 * LW + 6 * 2(WH + LH)$

$Cost = 9 * LW + 12(WH + LH)$

$Cost = 9 * LW + 12H(W + L)$

Substitute: $H = \frac{64}{W^2}$ and $L = 2W$

$Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)$

$Cost =18W^2 + \frac{768}{W^2}*3W$

$Cost =18W^2 + \frac{2304}{W}$

To minimize the cost, we differentiate

$C' =2*18W + -1 * 2304W^{-2}$

Then set to 0

$2*18W + -1 * 2304W^{-2} =0$

$36W - 2304W^{-2} =0$

Rewrite as:

$36W = 2304W^{-2}$

Divide both sides by W

$36 = 2304W^{-3}$

Rewrite as:

$36 = \frac{2304}{W^3}$

Solve for $W^3$

$W^3 = \frac{2304}{36}$

$W^3 = 64$

Take cube roots

$W = 4$

Recall that:

$L = 2W$

$L = 2 * 4$

$L = 8$

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$H = \frac{64}{4^2}$

$H = \frac{64}{16}$

$H = 4$

Hence, the dimension that minimizes the cost is:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

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2 years ago

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Rashid [163]

Answer:

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3 years ago