One dozen = 12
15/12 = 1.25
The cost of one fruit tart is $1.25
6. One variable only so pretty straightforward.
length-x+4
width-x
x+x+4=80
2x=76
x=38
x+4=42
answer: length 42cm and width 38cm
7. Another money problem!
n-# of nickels
q-# of quarters
n=3+q
0.05n+0.25q=2.85
Substitution works like a charm!
0.05(3+q)+0.25q=2.85
0.15+0.05q+0.25q=2.85
0.3q=2.7
q=9
n=3+q
n=3+9
n=12
answer: 9 nickels and 12 quarters
8. One variable situation again.
Ann's money-2b+9
Betty's money-b
b+2b+9=60
3b=51
b=17
2b+9=43
answer: Ann has $43 and Betty has $17.
9. # of red m&m's-x+1
# of blue m&m's-x
x+1+x=13
x=6
x+1=7
answer: 6 blue and 7 red m&m's
10. a-number of adult tickets
s-number of student tickets
a+s=785 ----> a=785-s
5a+2s=3280
5(785-s)+2s=3280
-3s=-645
s=215
a+s=785
a+215=785
a=570
answer: 215 children tickets and 570 adult tickets
<u>Work 1:</u>
Successful Percent:
15 divided by 20 equals .75
.75 times 100 is equal to 75
75%
Not successful Percent:
100% minus 75% equals 25%
<em>25%</em>
<u>Work 2:</u><u />
20 minus 15 equals 5
5 divided by 20 is equal to .25
.25 times 100 is equal to 25
<em>25%</em>
Answer:
The number of days is at most 5 days
= d ≤ 5 days
Step-by-step explanation:
A rental car company charges $31 per day to rent a car and $0.13 for every mile driven. Jocelyn wants to rent a car, knowing that:
She plans to drive 500 miles.
• She has at most $220 to spend.
At most means Less than or equal to $220
The inequality for expressing this = ≤
Hence, the inequality which can be used to determine d, the number of days Jocelyn can afford to rent while staying within her budget.
$31 × d + $0.13 × 500 miles ≤ $200
The inequality is given as:
31d + 65 ≤ 220
Solving further
31d ≤ 220 -65
31d ≤ 155
d ≤ 155/31
d ≤ 5
Therefore, the number of days is at most 5 days
Pretty sure the answer is 8
