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3 years ago

Find the discriminant and the numbers of real roots for this equation: 4x^2+12x+9=0

Mathematics

1 answer:

Len [333]3 years ago

8 0

Answer:

$D=0$

The quadratic equation has one real root with a multiplicity of 2.

Step-by-step explanation:

Given a quadratic equation:

$ax^2+bx+c=0$

You can find the Discriminant with this formula:

$D=b^2-4ac$

In this case you have the following quadratic equation:

$4x^2+12x+9=0$

Where:

$a=4\\b=12\\c=9$

Therefore, when you substitute these values into the formula, you get that the discriminant is this:

$D=(12)^2-4(4)(9)\\\\D=0$

Since $D=0$ , the quadratic equation has one real root with a multiplicity of 2 .

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Answer:

13. c,

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Step-by-step explanation:

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