Question

Find the discriminant and the numbers of real roots for this equation: 4x^2+12x+9=0

Answer 1

Answer:

$D=0$

The quadratic equation has one real root with a multiplicity of 2.

Step-by-step explanation:

Given a quadratic equation:

 $ax^2+bx+c=0$

You can find the Discriminant with this formula:

$D=b^2-4ac$

In this case you have the following quadratic equation:

$4x^2+12x+9=0$

Where:

$a=4\\b=12\\c=9$

Therefore, when you substitute these values into the formula, you get that the discriminant is this:

$D=(12)^2-4(4)(9)\\\\D=0$

Since $D=0$, the quadratic equation has one real root with a multiplicity of 2 .