Foci of ellipse of 3x2 + y2 =9
1 answer:
Answer:
x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3
Step-by-step explanation:
Let's solve for x.
3x2+y2=9
Step 1: Add -y^2 to both sides.
3x2+y2+−y2=9+−y2
3x2=−y2+9
Step 2: Divide both sides by 3.
3x^2/3= -y^2+9/3
x^2=-1/3 y^2 +3
x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3
Hope it helped!
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Answer:
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