Answer:
See explanation
Step-by-step explanation:
You are given the equation of the curve

Point
lies on the curve.
Point
is an arbitrary point on the curve.
The slope of the secant line PQ is
![\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]](https://tex.z-dn.net/?f=%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%3D%5Cdfrac%7B%5Cfrac%7Bx%7D%7B1%2Bx%7D-%5Cfrac%7B1%7D%7B2%7D%7D%7Bx-1%7D%3D%5Cdfrac%7B%5Cfrac%7B2x-%281%2Bx%29%7D%7B2%28x%2B1%29%7D%7D%7Bx-1%7D%3D%5Cdfrac%7B%5Cfrac%7B2x-1-x%7D%7B2%28x%2B1%29%7D%7D%7Bx-1%7D%3D%5C%5C%20%5C%5C%3D%5Cdfrac%7B%5Cfrac%7Bx-1%7D%7B2%28x%2B1%29%7D%7D%7Bx-1%7D%3D%5Cdfrac%7Bx-1%7D%7B2%28x%2B1%29%7D%5Ccdot%20%5Cdfrac%7B1%7D%7Bx-1%7D%3D%5Cdfrac%7B1%7D%7B2%28x%2B1%29%7D%5C%20%5B%5Ctext%7BWhen%7D%5C%20x%5Cneq%201%5D)
1. If x=0.5, then the slope is

2. If x=0.9, then the slope is

3. If x=0.99, then the slope is

4. If x=0.999, then the slope is

5. If x=1.5, then the slope is

6. If x=1.1, then the slope is

7. If x=1.01, then the slope is

8. If x=1.001, then the slope is
