1. 3n
2. 9x
3. 9wx
4. 5ac^2
5. 8wx^2
6. 4a^2 c
Answer:
(3 ± √23 * i) /4
Step-by-step explanation:
To solve this, we can apply the Quadratic Equation.
In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)
Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4
Plugging these values into our equation, we get
x = (-b ± √(b²-4ac))/(2a)
x = (-(-3) ± √(3²-4(2)(4)))/(2(2))
= (3 ± √(9-32))/4
= (3 ± √(-23))/4
= (3 ± √23 * i) /4
We can say at month 0 she was 43 inches tall.
And at month 18 she was 52 inches tall.
We can say that x is the number of months and y is her height.
Rise/run
y2-y1/x2-x1
52-43/18-0
9/18
1/2
So the slope is 1/2 (which is what you are looking for.) and if you were to write an equation it would be y=1/2x+43
Brainliest my answer if it helps you out?
How on earth is anyone suppose to answer this !!
62 / 15.5 = 92 / x
to find x cross multiply:-
62x = 15.5 * 92
x = (15.5*92) / 62
= 23
