We are asked to express the diagonal of a rectangle in terms of the width in which the area of the polygon is equal to 13 square feet. The area of teh rectangle is equal to length times width. That is 13 = lw; diagonal using pythagorean theorem is sqrt ( l2 + w2). Thus d = sqrt ( (13/w)2 + w2) = sqrt ( (169/w2 + w2) = sqrt ( (169 + w4)/w2) = 1/w sqrt (169 + w4)
Answer:
17(maybe)
Step-by-step explanation:
12-(-5)=17
Multiply 2^(-5) by 2^6. The correct result is 2^1, or just 2 (inches).
When discriminant >0, then it contrains 2 distinct real zeros.
Discriminant=6 and 6>0 so, you have 2 solutions.
Answer:
The cars are 10702ft apart
Step-by-step explanation:
Height of the plane from the high way = 5150ft
Considering Triangle ABD, we will be using SOHCAHTOA
Tan = Opposite/ Adjacent
Tan 54° = Y/5150
Y = 5150*tan54°
Y = 7088 ft
Considering Triangle ADC, Tan = Opposite/ Adjacent is also applicable
Tan 34° = X/5150
X = 5150*tan 54°
X = 3614ft
The distance between the two cars = (X+Y)
= 7088 + 3614
= 10702ft