If you mean what goes in the blanks, it is 5 for the first empty box and 10 for the second empty box.
Answer:


Step-by-step explanation:
Given
The translated triangles
Required
Find x and y
We have:


means:

Open bracket

Collect like terms


Divide by 6

means

Open bracket

Collect like terms


Divide by 2

Answer:
-4/5
Step-by-step explanation:
To find the slope of the tangent to the equation at any point we must differentiate the equation.
x^3y+y^2-x^2=5
3x^2y+x^3y'+2yy'-2x=0
Gather terms with y' on one side and terms without on opposing side.
x^3y'+2yy'=2x-3x^2y
Factor left side
y'(x^3+2y)=2x-3x^2y
Divide both sides by (x^3+2y)
y'=(2x-3x^2y)/(x^3+2y)
y' is the slope any tangent to the given equation at point (x,y).
Plug in (2,1):
y'=(2(2)-3(2)^2(1))/((2)^3+2(1))
Simplify:
y'=(4-12)/(8+2)
y'=-8/10
y'=-4/5
Answer:
Hello! Your answer is less than. (<)
Step-by-step explanation:
I took the test and got it right, proof below!!!!
Hope this helps!! so so sorry if im late! <3