All categories

3 years ago

Compare 3.6 to the square root of 12

Mathematics

2 answers:

Likurg_2 [28]3 years ago

7 0

Answer:

The number 3.6 is greater than the number 3.464

Step-by-step explanation:

Consider the provided numbers.

3.6 and √12.

First convert the √12 into decimal form.

The value of √12 is approximately 3.464

Now we need to compare the number 3.6 and 3.464

Since the tenths place value of the number 3.6 is greater than the tenths place value of the number 3.464

The number 3.6 is greater than the number 3.464

Burka [1]3 years ago

3 0

The square root of 12 is 3.4641 so 3.6 would be greater than 3.4641

You might be interested in

Please answer these questions in the image ( click image to see fully )

drek231 [11]

9) x= -7

10) x= 10

11) x= 5

12) x= 6

13) x= 4

14) x= -9

15) x= 3

16) x= 9

sorry it took so long! hope this helps!! :)

5 0

3 years ago

Uniforms are sold in packages of 8. The stores 127 employees will each be given 3 uniforms. How many packages will the store nee

Mama L [17]

You would divide 127 by 8 then multiply that answer by three sirts each.

8 0

3 years ago

The sum of two numbers is 361 and the difference between the two numbers is 173. What are the two numbers?

Anika [276]

Divide 361 by 2
180.5
Divide 173 by 2
86.5
180.5+86.5=267
One of the # is 267
361-267=94
The other is 94

8 0

3 years ago

What is the answer to this question?

melisa1 [442]

Answer: I think it is negative.

Step-by-step explanation: When you add a negative to a negative you still have a negative.

7 0

4 years ago

The manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .

Misha Larkins [42]

Answer:

0.1507 or 15.07%.

Step-by-step explanation:

We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.

First of all, we will find z-scores for data points using z-score formula.

$z=\frac{x-\mu}{\sigma}$ , where,

z = z-score,

x = Sample score,

$\mu$ = Mean,

$\sigma$ = Standard deviation.

$z=\frac{21.97-22}{0.016}$

$z=\frac{-0.03}{0.016}$

$z=-0.1875$

Let us find z-score of data point 22.03.

$z=\frac{22.03-22}{0.016}$

$z=\frac{0.03}{0.016}$

$z=0.1875$

Using probability formula $P(a$ , we will get:

$P(-0.1875$

Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.

6 0

4 years ago