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zimovet [89]
4 years ago
6

Primary seismic waves are slow-moving and are examples of transverse waves. True False

Chemistry
2 answers:
zhenek [66]4 years ago
8 0
False, Primary Seismic Waves (P-Waves) are Longitudinal<span> or Compressional W</span><span>aves. It is the Secondary Seismic Waves (S-Waves) ((creative names)) are the Transverse Waves.</span>
Dafna1 [17]4 years ago
8 0

Answer:

False, Hope this Helps

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A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius? Ple
miskamm [114]

Answer:

648.5 mL

Explanation:

Here we will assume that the pressure of the gas is constant, since it is not given or specified.

Therefore, we can use Charle's law, which states that:

"For an ideal gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically:

\frac{V}{T}=const.

where

V is the volume of the gas

T is its absolute temperature

The equation can be rewritten as

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where in this problem we have:

V_1=490 mL is the initial volume of the gas

T_1=-35.0^{\circ} + 273 = 238 K is the initial temperature

T_2=42.0^{\circ}+273=315 K is the final temperature

Solving for V2, we find the final volume of the gas:

V_2=\frac{V_1 T_2}{T_1}=\frac{(490)(315)}{238}=648.5 mL

8 0
4 years ago
Calculate the final temperature of the system: A 50.0 gram sample of water initially at 100 °C and a 100 gram sample initially a
katrin2010 [14]

Answer:

The final temperature of the system is 42.46°C.

Explanation:

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c\times (T_f-T_1)=-(m_2\times c\times (T_f-T_2))

where,

c = specific heat of water= 4.18J/g^oC

m_1 = mass of water sample with 100 °C= 50.0 g

m_2 = mass of water sample with 13.7 °C= 100.0 g

T_f = final temperature of system

T_1 = initial temperature of 50 g of water sample= 100^oC

T_2 = initial temperature of 100 g of water =13.7^oC

Now put all the given values in the given formula, we get

50.0 g\times 4.184 J/g^oC\times (T_f-100^oC)=-(100 g\times 4.184 J/g^oC\times (T_f-13.7^oC))

T_f=42.46^oC

The final temperature of the system is 42.46°C.

5 0
4 years ago
Which examples represent chemical changes? Check all that apply.
VARVARA [1.3K]

Answer: Burning wood, souring milk, browning of a cut apple

5 0
3 years ago
Read 2 more answers
An atom of boron has an atomic number of 5 and an atomic mass of 11. The atom contains (2 points)
Nesterboy [21]

C) 5 protons, 5 electrons, and 6 neutrons

7 0
4 years ago
2PbS(s) + 3O2(g)  2PbO(s) + 2SO2(g) H = -827.4 kJ What is the volume of sulfur dioxide produced at STP if 975 kJ of heat are l
Akimi4 [234]

Answer:

52.79 dm3 of SO2 will be produced when 975kJ/mol of heat are liberated.

Explanation:

In the reaction given;

2PbS(s) + 3O2(g)  2PbO(s) + 2SO2(g)                                H = -827.4 kJ/mol

-827.4 kJ/mol of heat liberates 2 moles of SO2 in the reaction involving lead and oxygen

At STP, -827.4 kJ/mol of heat liberate 22.4 * 2 dm3 of SO2

So therefore, 975 kJ/mol of heat will liberate

= 975 * 22.4 * 2 / -827.4

= 43 680 / -827.4

= 52.79 dm3 of SO2.

52.79 dm3 of SO2 will be produced at STP if 975 kJ/mol of heat are liberated.

6 0
3 years ago
Read 2 more answers
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