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maksim [4K]
3 years ago
15

Can 46.65 be used for minutes?

Mathematics
2 answers:
jasenka [17]3 years ago
8 0
The answer is 2799 seconds.
omeli [17]3 years ago
7 0
?  46.65 minutes is 46 min 39 sec

Not sure what you were asking....
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I need graph help plz ​
Likurg_2 [28]

Answer:

Step-by-step explanation:

Part A

x-intercepts of the graph → x = 0, 6

Maximum value of the graph → f(x) = 120

Part B

Increasing in the interval → 0 ≤ x ≤ 3

Decreasing in the interval → 3 < x ≤ 6

As the price of goods increase in the interval [0, 3], profit increases.

But in the price interval of (3, 6] profit of the company decreases.

Part C

Average rate of change of a function 'f' in the interval of x = a and x = b is given by,

Average rate of change = \frac{f(b)-f(a)}{b-a}

Therefore, average rate of change of the function in the interval x = 1 and x = 3 will be,

Average rate of change = \frac{f(3)-f(1)}{3-1}

                                         = \frac{120-60}{3-1}

                                         = 30

6 0
3 years ago
A fish tank that is 5 feet long by 3 feet wide by 3 feet high has a 2 foot cubic stone placed in the bottom how much water will
maks197457 [2]

Answer:

37ft³

Step-by-step explanation:

Volume of the fish tank = length × width × height = 5ft × 3ft × 3ft = 45ft³

Volume of the cubic stone = length × length × length = (2ft)³ = 8ft³

Volume of the water = volume of the fish tank - volume of the cubic stone

i.e Volume of the water = 45ft³ - 8ft³ = 37ft³

4 0
3 years ago
What is the value of L-1.1)?<br> O —2<br> 0 -1<br> 0<br> O 1
Kazeer [188]

Answer:

I do not understand.

Step-by-step explanation:

Please add a picture of explain what it is you want help with.

At this moment I do not understand the question, I am sorry.

7 0
3 years ago
Read 2 more answers
Please help help help help help please ASAP
lora16 [44]

Answer

~~~~~~~~~~~~

slope: 1

y intercept: 4

equation: y=x+4

6 0
3 years ago
Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for the function. (
Mrrafil [7]

Answer:

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

Step-by-step explanation:

From exercise we have the next function y = 6 sec(3x).

We know that Maclaurin series for the function sec x, have the following form:

\sec x=1+\frac{x^2}{2}+\frac{5x^4}{24}+...

So, for the given function y = 6 sec(3x), we get:

y = 6 \sec(3x)=6+27x^2+\frac{405x^4}{4}+...

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

6 0
3 years ago
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