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3 years ago

Fixed costs may be relevant in a decision. A. True B. False

Business

1 answer:

zhuklara [117]3 years ago

5 0

Answer:

A. True

Explanation:

Fixed costs can be defined as predetermined expenses in a business that remain constant for a specific period of time regardless of the quantity of production or level of outputs. Some examples of fixed costs in business are loan payments, employee salary, depreciation, rent, insurance, lease, utilities etc.

Fixed costs may be relevant in a decision because it affects the amount of future cash-flow of a business entity.

For instance, the high fixed costs are usually a determinant for pricing a product that aren't produced in mass because to break even, businesses would need to rake in more revenues to meet the the increasing (high) fixed costs.

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The actual interest rate on a loan that is compounded monthly but expressed as an annual rate is referred to as the _____ rate.

Brrunno [24]

annual percentage rate

The effective tax rate of return from an investment for a year, taking into account compound interest, is known as the annual percentage yield (APY). The amount that lenders charge borrowers as a proportion of the principle is called the interest rate. Additionally, it is the sum derived from deposit accounts.

The annual interest produced by an amount that is paid to investors or levied to borrowers is referred to as the annual percentage rate (APR). APR is a percentage that expresses the real annual cost of borrowing money throughout the course of a loan or the revenue from an investment. This does not account for compounding and includes any fees or other expenditures related to the transaction.

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3 0

1 year ago

At an inflation rate of 7 percent, the purchasing power of $3 would be cut in half in 10.25 years. how long to the nearest year

lyudmila [28]

The applicable formula is;
A = P(1-r)^n

Where;
A = Final purchasing power
P = Current purchasing power
r = inflation
n = Number of years when P changes to A

Confirming the first claim:
A = 1/2P (to be confirmed)
P = $3
r = 7% = 0.07
n = 10.25 years

Using the formula;
A = 3(1-0.07)^10.25 = 3(0.475) ≈ 3(0.5) = $1.5
And therefore, A = 1/2P after 10.25 years.

Now, give;
P = $9
A = 1/4P = $9/4 = $2.25
r = 6.5% = 0.065
n = ? (nearest year).

Substituting;
2.25 = 9(1-0.065)^n
2.25/9 = (1-0.065)^n
0.25 = (1-0.065)^n
ln (0.25)= n ln(1-0.065)
-1.3863 = -0.0672n
n = (-1.3863)/(-0.0672) = 20.63 years

To nearest year;
n = 21 years

Therefore, it would take approximately 21 years fro purchasing power to reduce by 4. That is, from $9 to $2.25.

7 0

3 years ago

The Wall Street Journal reported the following spot and forward rates for the Swiss franc ($/SF):Spot...........................

Gnoma [55]

Answer:

The Wall Street Journal Reports

a. The Swiss franc was selling at a premium in the forward market.

b. The 30-day forward premium was: $0.0049.

c. The 90-day forward premium was: $0.0099.

d. Dollars to receive from a 90-day forward contract is $95,310.

Explanation:

a) Data and Calculations:

Spot and forward rates for the Swiss franc ($/SF):

Spot............................................ $0.9432

30-day forward.......................... $0.9481

90-day forward.......................... $0.9531

180-day forward........................ $0.9594

Premium:

30-day forward.......................... $0.9481

Spot............................................ $0.9432

Premium = $0.0049

90-day forward.......................... $0.9531

Spot............................................ $0.9432

Premium = $0.0099

180-day forward........................ $0.9594

Spot............................................ $0.9432

Premium = $0.0162

Dollars to receive from a 90-day forward contract is $95,310 ($0.9531 * SF 100,000)

6 0

3 years ago

Janet needs to assign a very important advertising account to one of her writers. First she reviewed each writer's work load,

S_A_V [24]

Answer:

D. systematic study

Explanation:

7 0

3 years ago

A tire without good traction has less _____.

zavuch27 [327]

Answer:

A tire without good traction has less grip on the road.

Explanation:

during inclement weather, especially snow and ice, even if properly inflated, the tire will spin but not move forward & driver will not have control over the vehicle, causing the vehicle to slip sideways into (other traffic, over the side of the road, possibly falling over a steep decent).

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3 0

2 years ago

Read 2 more answers