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andrew11 [14]
3 years ago
5

GeorgeIs holding a card with the number 66 written on it this card is the LCM of six and another number the other number is betw

een 15 and 25 find the other number
Mathematics
1 answer:
satela [25.4K]3 years ago
4 0

Answer:

The other number is 22.

Step-by-step explanation:

66 is the lowest common multiple of 6 and a number between 15 and 25.

The numbers between 15 and 25 include 16, 17, 18, 19, 20, 21, 22, 23 and 24.

Of all these numbers between 15 and 25, only 22 can divide 66 without a remainder.

And conveniently, the lowest common multiple of 6 and 22 is 66.

Hence, the other number is evidently 22.

Hope this Helps!!!

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A tree that grows 3 feet every 5 years is growing at a rate of ___ feet per year.
Anni [7]
Answer: 0.6

Reason: 3 divide by 5 is 0.6
8 0
3 years ago
Read 2 more answers
If a can is 20cm Haigh X 8cm diameter what is the volume
sattari [20]
Radius=8/2=4cm

volume=4*4*3.14*20=1004.8

The answer is  1004.8cm₃

7 0
3 years ago
Can someone help me pls ?
r-ruslan [8.4K]

Answer:

58.3%

Step-by-step explanation:

Add up the numbers that are only in one circle

18+7+10 = 35

Take this over 60

35/60=.58333333

Change to percent form to one decimal place

58.3%

3 0
2 years ago
Question 5
Vikentia [17]

The amount of sales (S) of statin in billions of dollars by 2017 is 34.5 billions

<h3>Linear equations</h3>

Linear equation are equation that has a leading degree of 1. Given the equation that represents Statins used to keep cholesterol in check and are a top-selling drug in the U.S.

S-1.5x = 6

where

S is the amount of sales

x is the number of years after 1998

By 2017, the total number of  years is 19 years

Substitute

S = 1.5x + 6

S = 1.5(19) + 6

S = 28.5 + 6

S = 34.5

The amount of sales (S) of statin in billions of dollars by 2017 is 34.5 billions

Learn more on linear equation here: brainly.com/question/14323743

#SPJ1

6 0
1 year ago
In a class of 50 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose
Tems11 [23]

Answer:  3

Step-by-step explanation:

Let E be the event of that student pierces ear and N be the event of that student pierces nose.

Given: n(E\cup N=50)

n(E)=46\\\\n(N)=7

For any two event A and B, we have

n(A\cup B)=n(A)+n(B)-n(A\cap B)

Similarly , n(E\cup N)=n(E)+n(N)-n(E\cap N)

50=46+7-n(E\cap N)\\\\\Rightarrow\ n(E\cap N)=53-50=3

Hence, 3 students have piercings both on their ears and their noses.

7 0
3 years ago
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