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andrew11 [14]
4 years ago
5

GeorgeIs holding a card with the number 66 written on it this card is the LCM of six and another number the other number is betw

een 15 and 25 find the other number
Mathematics
1 answer:
satela [25.4K]4 years ago
4 0

Answer:

The other number is 22.

Step-by-step explanation:

66 is the lowest common multiple of 6 and a number between 15 and 25.

The numbers between 15 and 25 include 16, 17, 18, 19, 20, 21, 22, 23 and 24.

Of all these numbers between 15 and 25, only 22 can divide 66 without a remainder.

And conveniently, the lowest common multiple of 6 and 22 is 66.

Hence, the other number is evidently 22.

Hope this Helps!!!

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Answer:

The answer is B

Step-by-step explanation:

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3 years ago
Which point on the graph of g(x)=(1/5)^x? HELPP
Cloud [144]

Answer:

(-1,5) and (3, \frac{1}{125}) are points on the graph

Step-by-step explanation:

Given

g(x) = \frac{1}{5}^x

Required

Determine which point in on the graph

To get which of point A to D is on the graph, we have to plug in their values in the given expression using the format; (x,g(x))

A. (-1,5)

x = -1

Substitute -1 for x in g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^{-1}

Convert to index form

g(x) = 1/(\frac{1}{5})

Change / to *

g(x) = 1*(\frac{5}{1})

g(x) = 5

This satisfies (-1,5)

<em>Hence, (-1,5) is on the graph</em>

<em></em>

B. (1,0)

x = 1

Substitute 1 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^1

g(x) = \frac{1}{5}

<em>(1,0) is not on the graph because g(x) is not equal to 0</em>

C. (3, \frac{1}{125})

x = 3

Substitute 3 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^3

Apply law of indices

g(x) = \frac{1}{5} * \frac{1}{5} * \frac{1}{5}

g(x) = \frac{1}{125}

This satisfies (3, \frac{1}{125})

<em>Hence, </em>(3, \frac{1}{125})<em> is on the graph</em>

<em></em>

D.  (-2, \frac{1}{25})

x = -2

Substitute -2 for x

g(x) = \frac{1}{5}^x

g(x) = \frac{1}{5}^{-2}

Convert to index form

g(x) = 1/(\frac{1}{5}^2)

g(x) = 1/(\frac{1}{5}*\frac{1}{5})

g(x) = 1/(\frac{1}{25})

Change / to *

g(x) = 1*(\frac{25}{1})

g(x) = 25

This does not satisfy  (-2, \frac{1}{25})

<em>Hence, </em> (-2, \frac{1}{25})<em> is not on the graph</em>

8 0
3 years ago
What is the value of ▲ in the equation shown? [▲x4]+[6x3]=6[4+3
daser333 [38]

Answer: 6

Step-by-step explanation:   [▲x4]+[6x3]=6[4+3

6[4+3=42 so if [6x3]=18 then [▲x4] needs to be 24 (24+18=42) ▲=6 as 6x4=24+18=42 (6[4+3)!

3 0
2 years ago
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