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frez [133]
2 years ago
12

What is the difference of 23× and 9×

Mathematics
1 answer:
allsm [11]2 years ago
8 0
23x and 9x are alike terms so
23x-9x
14x
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3(2 + f) = -15<br><br>A. 3<br>B. 7<br>C. -3<br>D. -7​
Scilla [17]

Answer:

D. (-7)

Step-by-step explanation:

3(2 + f) = (-15)

(3 . 2) + (3 . f) = (-15)

6 + 3f = (-15)

3f = (-15) - 6

3f = (-21)

f = (-21)/3

f = (-7)

5 0
2 years ago
Read 2 more answers
100 POINTS!!!! Create a table of values for a linear function. A drone is in the distance, flying upward in a straight line. It
dangina [55]
Based on the docx you showed me, the equation for the parabola is y = x^2 + 36 and you want a table of values for a linear equation that intersects the parabola at (5, 6) and (-2, 34).

If you use these two points to create a line we get the equation:

y - 6 = \frac{34 - 6}{-2 - 5}(x - 5) (I just used point slope form)

This can be simplified to:

y = \frac{40}{-7}x + \frac{242}{7}

Now we just need to create a table of points on this line. We already have the points you gave and we can also use the y-intercept: (0, \frac{242}{7}) and the x-intercept: (\frac{121}{20}, 0).

So our table of value can be:

x          | y
______|________
-2         | 34
0          | 242 / 7
5          | 6
121/20 | 0
3 0
2 years ago
Max bought a package of hamburger that weighs pounds. He needs of that amount for a recipe. How much hamburger does Max need for
kari74 [83]

5 1/3 is the answer to your problem


4 0
3 years ago
8 - 6x = 4 + 2x in verbal sentences
BartSMP [9]

Answer:

The difference of 6 times x subtracted from 8 is equal to the sum of 4 added to Twice x

6 0
2 years ago
Find the value of c so that (x+2) is a factor of the polynomial<br><br> p(x)=3x^4-x^2+cx-2
DedPeter [7]
Using polynomial long division, we get
         
         3x^3+6x^2+11x
         _____________
(x+2) | 3x^4-x^2+cx-2
          -(3x^4+6x^3)
          ____________
             6x^3-x^2+cx-2
          - (6x^3+12x^2)
         _____________
        11x^2+cx-2
      -(11x^2+22x) 
       __________
        (22+c)x-2. 

If you're wondering how I did the long division, what I essentially did was get the first value (at the start, it was 3x^4) and divided it by the first value of the divisor (which in x+2 was x) to get 3x^3 in our example. I then subtracted the polynomial by the whole divisor multiplied by, for example, 3x^3 and repeated the process.

For this to be a perfect factor, (x+2)*something must be equal to (22+c)x-2. Focusing on how to cancel out the 2, we have to add 2 to it. To add 2 to it, we have to multiply (x+2) by 1. However, there's a catch, which is that we subtract whatever we multiply (x+2) by, so we have to multiply it by -1 instead. We still need to cross out (22+c)x. Multiplying (x+2) by -1, we get
(-x-2) but by subtracting the whole thing from something means that we have to add -(-x-2)=x+2 to something to get 0. x+2-x-2=0, xo (22+c)x-2 must equal -x-2, meaning that (22+c)=-1 and c=-23
4 0
3 years ago
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