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3 years ago

Rotation 180 about the origin E(2,-2), J(1,2), R(3,3), S(5,2)

Mathematics

1 answer:

hammer [34]3 years ago

6 0

E' (-2, 2) , J'(-1, -2) , R'(-3,-3) , S'(-5, -2)

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The formula A equals =P left parenthesis 1 plus r right parenthesis squared (1+r)2 gives the amount A in dollars that P dollars

vlabodo [156]

The interest rate is 3.5%.

EXPLANATION

We substitute the given values into the formula;

$A=P(1+\frac{r}{100})^t$

to obtain

$6427.35=6000(1+\frac{r}{100})^2$

We divide through by 6000 to obtain,

$\frac{6427.35}{6000}=(1+\frac{r}{100})^2$

This implies that,

$1.071225=(1+\frac{r}{100})^2$

We take the square root of both sides,

$\sqrt{1.071225}=(1+\frac{r}{100})$

This gives us,

$1.035=(1+\frac{r}{100})$

Add -1 to both sides of the equation to obtain

$0.035=\frac{r}{100}$

Multiply through by 100 to obtain;

$r=3.5$ %

$Therefore the rate is 3.5%$

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3 years ago

Balloon Payment (Math)

fiasKO [112]

Answer:

Step-by-step explanation:

The loan duration is for 8 years, a total of 12·8 = 96 monthly payments. The 96th payment is the balloon payment.

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3 years ago

PLEASE ANSWER AS SOON AS POSSIBLE!

Tcecarenko [31]

The y- intercept has to be a point in the line where x is 0. Which means that in this case it would be -4.
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3 years ago

In a bag are 5 oranges and 4 mangoes select one replaces it and select another . What is the probability that both selections we

Serggg [28]

Answer:

P(orange)x P(orange)= 5/9 x 5/9= 25/81

Step-by-step explanation:

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3 years ago

How to evaluate the limit

anzhelika [568]

$\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}$

Both the numerator and denominator are continuous at $x=2$ , which means the quotient rule for limits applies:

$\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2$

Perhaps you meant to write that $x\to-2$ instead? In that case, you would have

$\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5$

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3 years ago

Rotation 180 about the origin E(2,-2), J(1,2), R(3,3), S(5,2)​

Rotation 180 about the origin E(2,-2), J(1,2), R(3,3), S(5,2)