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Katen [24]
3 years ago
14

Omar buys five shirts for $22 each, three pairs of pants for $50 each, and six ties for $17 each. What is the mean amount that h

e spent per article of clothing?
Mathematics
2 answers:
Serjik [45]3 years ago
5 0

mean = $29.67

To do this you add up all the numbers together and divide it by how many number there are. For this situation, because there is 3 numbers you would divide the number by 3.

Maksim231197 [3]3 years ago
3 0

Answer: $26.5

Step-by-step explanation:

From this question, we list out the data set

Data set = [22,22,22,22,22,50,50,50,17,17,17,17,17]

Mean amount spent per article of clothing = total sum of amount/frequency of amount

Mean = 345 /13

=$26.5

I hope this helps.

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Which functions are symmetric with respect to the origin?
Damm [24]

Answer:

The correct option is;

y = arcsinx and y = arctanx

Step-by-step explanation:

The given options are;

1) y = arcsinx and y = arccosx

Here, we have at the origin, where x = 0,  arccosx ≈ 1.57 while arcsinx = 0

Therefore arccosx does not intersect arcsinx at the origin for it to be symmetrical to arcsinx or the origin

2)  y = arccosxy and y = arctanx

Here arctanx = 0 when x = 0 and arcos x = 1.57 when x = 0 therefore, they are not symmetrical

3) y = arctanx and y = arccotx

Similarly, At x = 0, arccotx = 1.57 therefore, they are not symmetrical

4) y = arcsinx and y = arctanx

Both functions arcsinx and arctanx pass through the origin and their shapes are similar but inverted as they go from negative to positive.

3 0
3 years ago
A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y. That is, gi
defon

Answer:

An ordered pair is a set of inputs and outputs and represents a relationship between the two values. A relation is a set of inputs and outputs, and a function is a relation with one output for each input.

h

here is a exstended explantion:

A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y. That is, given an element x in X, there is only one element in Y that x is related to.

For example, consider the following sets X and Y. I'll give you a relation between them that is not a function, and one that is.

   X = { 1, 2, 3 }

   Y = { a , b , c, d }

   Relation from X to Y (i.e., in XxY ) : { (1,a) , (2, b) , (2, c) , (3, d) }

This relation is not a function from X to Y because the element 2 in X is related to two different elements, b and c. (Note, if you transpose the ordered pairs you <i>would</i> have a function from Y to X - can you see WHY?)

   Relation from X to Y that is a function: { (1,d) , (2,d) , (3, a) }

This is a function since each element from X is related to only one element in Y. Note that it is okay for two different elements in X to be related to the same element in Y. It's still a function, it's just not a one-to-one function.

8 0
3 years ago
Are these triangles similar<br><br> Please hurry!
mezya [45]

Answer:

no they are not

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
*the problem is in the pic that is uploaded
Alex787 [66]
Hmm,
ok,
complete square ok
wait wat

he went from
(x-3)²=16 to
x-3=16
?????
he square rooted the left side only
he has to do it to both sides

he should have done
(x-3)²=16
x-3=+/-4
x=3+/-4
x=7 or -1
8 0
3 years ago
An object is heated to 100°. It is left to cool in a room that
stepladder [879]

Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

T₁ = 30

T₀ = 100

t = 5

k = ?

Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

-.3364722366=5k

Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

3 0
3 years ago
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